I am just starting to lean MIPS assembly, and I am trying to write a simple while
loop. It will be equivilent to the C code:
我刚刚开始倾向于MIPS汇编,我正在尝试编写一个简单的while循环。它将与C代码等效:
int A[5];
for(i=0;i<5;i++) A[i]=i;
So I know I can use beq
to make a while
loop, but I don't know how to increment the memory address each time to go to the next register. I think maybe the slt
operand may be useful, but I don't know.
所以我知道我可以使用beq来做一个while循环,但我不知道如何每次增加内存地址以转到下一个寄存器。我想也许slt操作数可能有用,但我不知道。
2 个解决方案
#1
assuming $3 points to A[]
假设A []为3美元
lis $4
.word 4
lis $5
.word 1
add $7, $4, $5 ;$7 = 5
add $6, $0, $0 ;$6 = 0
loop:
sw $6, 0($3)
add $3, $4, $3 ;point to next "int"
add $6, $5, $6 ;add 1 to our counter
bne $7, $6, loop ;we will stop at 5
#2
.data
A: .space 20 #declared 20 bytes of storage to hold array of 5 int
__start:
lw $t0, A #load base address of array
li $t1, 0
loop: sw $t1($t0), $t1
addi $t1, $t1, 4
ble $t1, 20, loop
#continue code or simple exit after this
#1
assuming $3 points to A[]
假设A []为3美元
lis $4
.word 4
lis $5
.word 1
add $7, $4, $5 ;$7 = 5
add $6, $0, $0 ;$6 = 0
loop:
sw $6, 0($3)
add $3, $4, $3 ;point to next "int"
add $6, $5, $6 ;add 1 to our counter
bne $7, $6, loop ;we will stop at 5
#2
.data
A: .space 20 #declared 20 bytes of storage to hold array of 5 int
__start:
lw $t0, A #load base address of array
li $t1, 0
loop: sw $t1($t0), $t1
addi $t1, $t1, 4
ble $t1, 20, loop
#continue code or simple exit after this