In eclipse, when I code in Java, there is a feature to auto-generate a basic, efficient, and bug free implementation of hashCode()
and equals()
without consuming brain power.
在eclipse中,当我用Java编写代码时,有一个特性可以自动生成基本的、高效的、无bug的hashCode()和equals()实现,而不需要耗费脑力。
Is there a similar feature either built-in in Visual Studio or in ReSharper ?
在Visual Studio或ReSharper中是否有类似的特性?
2 个解决方案
#1
52
Yes, Resharper can do that. With cursor inside your type, open the “Generate code” menu (Alt+Ins depending on settings or Resharper -> Edit -> Generate Code), and select “Equality members”:
是的,Resharper做到了。将光标放在你的类型中,打开“生成代码”菜单(Alt+Ins取决于设置或Resharper ->编辑->生成代码),选择“平等成员”:
This opens a window where you can select which members are used for equality, along with some options about the generated code (e.g. should your type implement IEquatable<T>
):
这将打开一个窗口,在那里您可以选择使用哪些成员进行平等,以及关于生成代码的一些选项(例如,您的类型是否实现了IEquatable
If you start with a simple type with two properties:
如果您从具有两个属性的简单类型开始:
class Person
{
public string FirstName { get; private set; }
public string LastName { get; private set; }
}
Then the generated code may look something like:
然后生成的代码看起来可能如下所示:
class Person : IEquatable<Person>
{
public string FirstName { get; private set; }
public string LastName { get; private set; }
public bool Equals(Person other)
{
if (ReferenceEquals(null, other))
return false;
if (ReferenceEquals(this, other))
return true;
return string.Equals(FirstName, other.FirstName) && string.Equals(LastName, other.LastName);
}
public override bool Equals(object obj)
{
if (ReferenceEquals(null, obj))
return false;
if (ReferenceEquals(this, obj))
return true;
if (obj.GetType() != this.GetType())
return false;
return Equals((Person)obj);
}
public override int GetHashCode()
{
unchecked
{
return ((FirstName != null ? FirstName.GetHashCode() : 0) * 397) ^ (LastName != null ? LastName.GetHashCode() : 0);
}
}
}
#2
0
Since you asked if also Visual Studio can do that: since XI.2017 it finaly can generate something useful.
既然你问过Visual Studio是否也能做到这一点:从2017年起,它最终会产生一些有用的东西。
Using ctr+. inside class and choosing "Generate Equals and GetHashCode"
使用ctr +。在类中选择“生成Equals和GetHashCode”
See https://*.com/a/48441971/4547594
参见https://*.com/a/48441971/4547594
#1
52
Yes, Resharper can do that. With cursor inside your type, open the “Generate code” menu (Alt+Ins depending on settings or Resharper -> Edit -> Generate Code), and select “Equality members”:
是的,Resharper做到了。将光标放在你的类型中,打开“生成代码”菜单(Alt+Ins取决于设置或Resharper ->编辑->生成代码),选择“平等成员”:
This opens a window where you can select which members are used for equality, along with some options about the generated code (e.g. should your type implement IEquatable<T>
):
这将打开一个窗口,在那里您可以选择使用哪些成员进行平等,以及关于生成代码的一些选项(例如,您的类型是否实现了IEquatable
If you start with a simple type with two properties:
如果您从具有两个属性的简单类型开始:
class Person
{
public string FirstName { get; private set; }
public string LastName { get; private set; }
}
Then the generated code may look something like:
然后生成的代码看起来可能如下所示:
class Person : IEquatable<Person>
{
public string FirstName { get; private set; }
public string LastName { get; private set; }
public bool Equals(Person other)
{
if (ReferenceEquals(null, other))
return false;
if (ReferenceEquals(this, other))
return true;
return string.Equals(FirstName, other.FirstName) && string.Equals(LastName, other.LastName);
}
public override bool Equals(object obj)
{
if (ReferenceEquals(null, obj))
return false;
if (ReferenceEquals(this, obj))
return true;
if (obj.GetType() != this.GetType())
return false;
return Equals((Person)obj);
}
public override int GetHashCode()
{
unchecked
{
return ((FirstName != null ? FirstName.GetHashCode() : 0) * 397) ^ (LastName != null ? LastName.GetHashCode() : 0);
}
}
}
#2
0
Since you asked if also Visual Studio can do that: since XI.2017 it finaly can generate something useful.
既然你问过Visual Studio是否也能做到这一点:从2017年起,它最终会产生一些有用的东西。
Using ctr+. inside class and choosing "Generate Equals and GetHashCode"
使用ctr +。在类中选择“生成Equals和GetHashCode”
See https://*.com/a/48441971/4547594
参见https://*.com/a/48441971/4547594