I have code like this (http://jsfiddle.net/tb7E9/1/):
我有这样的代码(http://jsfiddle.net/tb7E9/1/):
<script>
function listEvents(json) {
var feed = json.feed;
for (var i = 0; i < 3; i++) {
var entry = json.feed.entry[i];
var posttitle = entry.title.$t;
//Style
if (i == 0) {
x = "<span style='color:red'>Style 1 </span><p>" + posttitle + "</p>";
p = "<span style='color:red'>Style 2 </span><h4>" + posttitle + "</h4><p>";
}
if (i == 1) {
y = "<p>" + posttitle + "</p>";
g = "<h4>" + posttitle + "</h4></p>";
}
}
style1 = x + y; document.write(style1);
style2 = p + g; document.write(style2);
}
</script>
The second Script:
第二个脚本:
<script>
//How to style1 is actived and style2 is disable here?
document.write("<script src=\"http://www.allbloggertricks.com/feeds/posts/default/-/Tutorials?orderby=published&alt=json-in-script&callback=listEvents\"><\/script>");
</script>
I'd like to display only style (style1(normal text) or style2(bold text) as example in jsfiddle). It means if I choose style1 for display, then style2 is disable.
我只想显示样式(style1(普通文本)或style2(粗体文本)，如jsfiddle中的示例)。这意味着如果我选择style1作为显示，则style2是禁用的。
How can I change code in the second script to do that?
如何修改第二个脚本中的代码来实现这一点?
1 个解决方案
#1
1
This is the correct way to archive it.
这是正确的存档方式。
function Y (){
var window.X = *** ;
console.print(window.X):
console.print(X):
}
Y():
console.print(window.X):
#1
1
This is the correct way to archive it.
这是正确的存档方式。
function Y (){
var window.X = *** ;
console.print(window.X):
console.print(X):
}
Y():
console.print(window.X):