替换特定字符后的特定字符序列

I have the folowing string for example:

我有下面的字符串,例如:

O > O §o TEXT §r §o TEXT §r

I need to replace all §r with §r§a only after > character.

我需要在>字符之后用§r§a替换所有§r。

It should be

它应该是

O > O §o TEXT §r§a §o TEXT §r§a

as the result.

作为结果。

I tried >*(\§r) regex but it ignores >.

我尝试了> *(\§r)正则表达式,但它忽略了>。

May You point on my error?

你能指出我的错误吗?

3 个解决方案

#1

The easiest way to do this would be to split it into two strings first and then run a replace. That is, you could take

最简单的方法是首先将其拆分为两个字符串,然后运行替换。也就是说,你可以采取

int index = inputString.indexOf('>') + 1;
String first = inputString.subString(0, index);
String second = inputString.subString(index);
String finalString = first + second.replace("§r", "§r§a");

Doing this with a pure regular expression would be difficult.

使用纯正则表达式执行此操作将很困难。

#2

Description

((?:(?!>).)*>.*?|)(§r)

Replace With: $1§r§a

替换为:$1§r§a

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Example

Live Demo

https://regex101.com/r/xP8dI5/1

Sample text

§r O > O §o TEXT §r §o TEXT §r

After Replacment

§r O > O §o TEXT §r§a §o TEXT §r§a

Explanation

NODE                     EXPLANATION
----------------------------------------------------------------------
  (                        group and capture to \1:
----------------------------------------------------------------------
    (?:                      group, but do not capture (0 or more
                             times (matching the most amount
                             possible)):
----------------------------------------------------------------------
      (?!                      look ahead to see if there is not:
----------------------------------------------------------------------
        >                        '>'
----------------------------------------------------------------------
      )                        end of look-ahead
----------------------------------------------------------------------
      .                        any character except \n
----------------------------------------------------------------------
    )*                       end of grouping
----------------------------------------------------------------------
    >                        '>'
----------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
----------------------------------------------------------------------
   |                        OR
----------------------------------------------------------------------
  )                        end of \1
----------------------------------------------------------------------
  (                        group and capture to \2:
----------------------------------------------------------------------
    §r                      '§r'
----------------------------------------------------------------------
  )                        end of \2
----------------------------------------------------------------------

#3

A pure regex way is by using \G like following

纯正的正则表达方式是使用\ G,如下所示

(\G(?!\A)|>)(.*?)§r

and, replace with

并且,替换为

$1$2§r§a

Regex Demo

Java Code

System.out.println("O§r §r > O §o TEXT §r §o §r TEXT §r".replaceAll("(\\G(?!\\A)|>)(.*?)§r", "$1$2§r§a"));

Ideone Demo