I have a data table for which I want to aggregate the data based on multiple fields. Here is a simplified example of my data:
我有一个数据表,我想根据多个字段聚合数据。以下是我的数据的简化示例:
# each record is the number of pages read
# by a student in a given day
pages_per_day <- data.table(
student_id = c(1,1,1,2,2,2),
week_of_semester = c(1,1,2,1,2,2),
pages_read = c(8,6,4,7,8,7)
)
I would like to aggregate this data based on both student_id and week to show the average number of pages per each student read during a given week of the semester. I tried the following:
我想根据student_id和week聚合这些数据,以显示在学期的某一周内每位学生阅读的平均页数。我尝试了以下方法:
avg_weekly_pages_read <- grades[,list(
avg_pages = sum(pages_read) / .N,
by = c('student_id','week')
)]
This gives me a two column data table with columns: avg_pages, by.
这给了我一个包含列的两列数据表:avg_pages,by。
I was hoping to have a table more like:
我希望有一张桌子更像:
student_id, week, avg_pages
1,1,7
1,2,4
2,1,7
2,2,7.5
Any guidance is greatly appreciated.
非常感谢任何指导。
2 个解决方案
#1
You are looking for
你在找
pages_per_day[, .(avg_pages = mean(pages_read)), by = .(student_id, week_of_semester)]
# student_id week_of_semester avg_pages
# 1: 1 1 7.0
# 2: 1 2 4.0
# 3: 2 1 7.0
# 4: 2 2 7.5
Btw, no need to reinvent the wheel. There is a mean
functions in R
顺便说一句,没有必要重新发明*。 R中有一个平均函数
#2
aggregate(pages_read~student_id+week_of_semester,pages_per_day,mean)
student_id week_of_semester pages_read
# 1 1 1 7.0
# 2 2 1 7.0
# 3 1 2 4.0
# 4 2 2 7.5
#1
You are looking for
你在找
pages_per_day[, .(avg_pages = mean(pages_read)), by = .(student_id, week_of_semester)]
# student_id week_of_semester avg_pages
# 1: 1 1 7.0
# 2: 1 2 4.0
# 3: 2 1 7.0
# 4: 2 2 7.5
Btw, no need to reinvent the wheel. There is a mean
functions in R
顺便说一句,没有必要重新发明*。 R中有一个平均函数
#2
aggregate(pages_read~student_id+week_of_semester,pages_per_day,mean)
student_id week_of_semester pages_read
# 1 1 1 7.0
# 2 2 1 7.0
# 3 1 2 4.0
# 4 2 2 7.5