So here's my (java) string
所以这是我的(java)字符串
String s = "Some string preceding this {\"Key1\": \"Val1\", \"Key2\": {\"embedKey1\": \"embedVal1\", \"embedKey2\": \"embedVal2\"}, \"Key3\" : \"Val3\", \"Key3\": \"Val4\"}, some value proceeding it"
I want to get everything that is within the outer curly braces. How do I do that? So far I've tried the following
我想得到外花括号内的所有东西。我怎么做?到目前为止,我已尝试过以下内容
Pattern p = Pattern.compile("\\{([^}]*)\\}");
Matcher m = p.matcher(s);
while(m.find()){
System.out.println(m.group(1));
}
This however, only prints
但是,这只是打印
"Key1": "Val1", "Key2": {"embedKey1": "embedVal1", "embedKey2": "embedVal2"
Can someone please help me with this?
有人可以帮我这个吗?
3 个解决方案
#1
2
To get everything in between outer braces, or between the first {
and the last }
, use greedy matching with a .
matching all symbols (with DOTALL mode):
要在外括号之间或第一个{和最后一个}之间获取所有内容,请使用与a的贪婪匹配。匹配所有符号(使用DOTALL模式):
String s = "Some string preceding this {\"Key1\": \"Val1\", \"Key2\": {\"embedKey1\": \"embedVal1\", \"embedKey2\": \"embedVal2\"}, \"Key3\" : \"Val3\", \"Key3\": \"Val4\"}, some value proceeding it";
Pattern p = Pattern.compile("(?s)\\{(.*)}");
Matcher m = p.matcher(s);
while(m.find()){
System.out.println(m.group(1));
}
See IDEONE demo
请参阅IDEONE演示
The (?s)
is an inline version of the Pattern.DOTALL
modifier.
(?s)是Pattern.DOTALL修饰符的内联版本。
#2
0
For your particular example you can use a regex like this:
对于您的特定示例,您可以使用这样的正则表达式:
\{(.*?)\{.*?}(.*?)}
工作演示
Match information
匹配信息
MATCH 1
1. [40-64] `"Key1": "Val1", "Key2": `
2. [116-149] `, "Key3" : "Val3", "Key3": "Val4"`
On the other hand, if you want to even capture the inner curly braces you can use something easier like this:
另一方面,如果你想要捕捉内部花括号,你可以使用更简单的东西:
\{(.*)}
工作演示
Match information
匹配信息
MATCH 1
1. [40-149] `"Key1": "Val1", "Key2": {"embedKey1": "embedVal1", "embedKey2": "embedVal2"}, "Key3" : "Val3", "Key3": "Val4"`
QUICK REFERENCE
Remember to escape backslashes in java:
记得在java中转义反斜杠:
Pattern p = Pattern.compile("\\{(.*)}");
Matcher m = p.matcher(s);
while(m.find()){
System.out.println(m.group(1));
}
#3
0
If It's just about outermost "{" and "}" as you mentioned in your problem, this may be one of the non-regex approach.
如果你在问题中提到它只是最外面的“{”和“}”,这可能是非正则表达式之一。
int first=s.indexOf('{');
int last=s.lastIndexOf('}');
String result=s.substring(first, last+1);
#1
2
To get everything in between outer braces, or between the first {
and the last }
, use greedy matching with a .
matching all symbols (with DOTALL mode):
要在外括号之间或第一个{和最后一个}之间获取所有内容,请使用与a的贪婪匹配。匹配所有符号(使用DOTALL模式):
String s = "Some string preceding this {\"Key1\": \"Val1\", \"Key2\": {\"embedKey1\": \"embedVal1\", \"embedKey2\": \"embedVal2\"}, \"Key3\" : \"Val3\", \"Key3\": \"Val4\"}, some value proceeding it";
Pattern p = Pattern.compile("(?s)\\{(.*)}");
Matcher m = p.matcher(s);
while(m.find()){
System.out.println(m.group(1));
}
See IDEONE demo
请参阅IDEONE演示
The (?s)
is an inline version of the Pattern.DOTALL
modifier.
(?s)是Pattern.DOTALL修饰符的内联版本。
#2
0
For your particular example you can use a regex like this:
对于您的特定示例,您可以使用这样的正则表达式:
\{(.*?)\{.*?}(.*?)}
工作演示
Match information
匹配信息
MATCH 1
1. [40-64] `"Key1": "Val1", "Key2": `
2. [116-149] `, "Key3" : "Val3", "Key3": "Val4"`
On the other hand, if you want to even capture the inner curly braces you can use something easier like this:
另一方面,如果你想要捕捉内部花括号,你可以使用更简单的东西:
\{(.*)}
工作演示
Match information
匹配信息
MATCH 1
1. [40-149] `"Key1": "Val1", "Key2": {"embedKey1": "embedVal1", "embedKey2": "embedVal2"}, "Key3" : "Val3", "Key3": "Val4"`
QUICK REFERENCE
Remember to escape backslashes in java:
记得在java中转义反斜杠:
Pattern p = Pattern.compile("\\{(.*)}");
Matcher m = p.matcher(s);
while(m.find()){
System.out.println(m.group(1));
}
#3
0
If It's just about outermost "{" and "}" as you mentioned in your problem, this may be one of the non-regex approach.
如果你在问题中提到它只是最外面的“{”和“}”,这可能是非正则表达式之一。
int first=s.indexOf('{');
int last=s.lastIndexOf('}');
String result=s.substring(first, last+1);