列表输出截断-如何在R中使用str()扩展列出的变量。

时间:2021-09-11 00:10:22

I have a data.frame df with 600+ variables. I'm writing a function that automates the creation of columns and need to visually check them once.

我有一个data.frame df,有600多个变量。我正在编写一个函数来自动创建列,并需要对它们进行一次可视检查。

The str function provides a good summary:

str函数提供了一个很好的总结:

str(df)
'data.frame':   29 obs. of  602 variables:
 $ uniqueSessionsIni: POSIXct, format: "2015-01-05 15:00:00" "2015-01-05 16:00:00" "2015-01-05 17:00:00" ...
 $ uniqueSessionsEnd: POSIXct, format: "2015-01-05 15:59:00" "2015-01-05 16:59:00" "2015-01-05 17:59:00" ...
 $ m0p0             : POSIXct, format: "2015-01-05 15:00:00" "2015-01-05 15:00:00" "2015-01-05 15:00:00" ...
 $ m1p0             : POSIXct, format: "2015-01-05 15:01:00" "2015-01-05 15:01:00" "2015-01-05 15:01:00" ...
 $ m2p0             : POSIXct, format: "2015-01-05 15:02:00" "2015-01-05 15:02:00" "2015-01-05 15:02:00" ...    

and it goes on...
but truncates the output, as below:

它继续……但截断输出,如下:

$ m33p1            : POSIXct, format: "2015-01-05 15:34:00" "2015-01-05 15:34:00" "2015-01-05 15:34:00" ...
$ m34p1            : POSIXct, format: "2015-01-05 15:35:00" "2015-01-05 15:35:00" "2015-01-05 15:35:00" ...
$ m35p1            : POSIXct, format: "2015-01-05 15:36:00" "2015-01-05 15:36:00" "2015-01-05 15:36:00" ...
$ m36p1            : POSIXct, format: "2015-01-05 15:37:00" "2015-01-05 15:37:00" "2015-01-05 15:37:00" ...
[list output truncated]

How can I display the full list of 602 variables?

如何显示602个变量的完整列表?

2 个解决方案

#1


49  

You can use the argument list.len:

你可以使用参数列表。len:

str(df, list.len=ncol(df))

and if you want to print more observations you could set the argument vec.len, also have a look at ?str for documentation of all arguments.

如果你想打印更多的观测结果,你可以设置参数vec。len,还有一个关于所有参数的文档。

#2


6  

By using argument list.len one can choose the number of variables in the data frame to list. There are two options:

通过使用参数列表。len可以选择数据帧中的变量个数。有两个选择:

a) You choose the number of variables that you want to list;

a)您选择要列出的变量的数量;

str(df, list.len = 602) # in this case I'm listing 602 variables.

b) You choose to list the total number of variables of the data frame (as mentioned by user1981275);

b)您选择列出数据帧的变量总数(如user1981275所提到的);

str(df, list.len = ncol(df))

Check R help for more info

查看R帮助了解更多信息。

> ?str

#1


49  

You can use the argument list.len:

你可以使用参数列表。len:

str(df, list.len=ncol(df))

and if you want to print more observations you could set the argument vec.len, also have a look at ?str for documentation of all arguments.

如果你想打印更多的观测结果,你可以设置参数vec。len,还有一个关于所有参数的文档。

#2


6  

By using argument list.len one can choose the number of variables in the data frame to list. There are two options:

通过使用参数列表。len可以选择数据帧中的变量个数。有两个选择:

a) You choose the number of variables that you want to list;

a)您选择要列出的变量的数量;

str(df, list.len = 602) # in this case I'm listing 602 variables.

b) You choose to list the total number of variables of the data frame (as mentioned by user1981275);

b)您选择列出数据帧的变量总数(如user1981275所提到的);

str(df, list.len = ncol(df))

Check R help for more info

查看R帮助了解更多信息。

> ?str