将数据从jQuery传递到PHP以获取ajax帖子

Hello I am a newbie working with jQuery and Ajax. I am trying submit data to the server using Jquery POST method. And the data that I am passing is a string. Now I am unable to understand how do I pass the data and how do I retrieve the data. I have tried searching for articles for my problem, but I have found none. I believe my problem is very basic.

你好，我是一个使用jQuery和Ajax的新手。我正在尝试使用Jquery POST方法将数据提交到服务器。我传递的数据是一个字符串。现在我无法理解如何传递数据以及如何检索数据。我试过为我的问题搜索文章，但我没找到。我相信我的问题非常基础。

if (1)//validateStep(step)
{
if(step==1)
{
var data = document.getElementById('hiddenContact').value;
$.post('/callcenter/admin/postContacts', data);
}
}

Now I'll post the code for my postContacts action, which isn't a big thing.

现在我将发布我的postContacts动作的代码，这不是一件大事。

function postContacts()
{
$this->autoRender = false;
echo '<script>console.log("post contacts");</script>';
}

But I am confused as to how the data has to be retrieved. Any help is appreciated. I am using cakePHP, so I have had to use autoRender=false; which makes the view optional.

但我对如何检索数据感到困惑。任何帮助表示赞赏。我正在使用cakePHP，所以我不得不使用autoRender = false;这使视图可选。

3 个解决方案

#1

With jQuery post you can define a callback function which is executed when the data is returned:

使用jQuery post，您可以定义一个回调函数，该函数在返回数据时执行：

$.post('/callcenter/admin/postContacts', data, function(returnedData) {
    // do something here with the returnedData
    console.log(returnedData);
});

The data should be in the form:

数据应采用以下形式：

{name: 'value', anotherName: 'another value'}

which equates to the post names on the PHP end accessible in plain PHP like this:

这相当于PHP端的帖子名称可以在普通的PHP中访问，如下所示：

echo $_POST['name'];           # prints "value"
echo $_POST['anotherName'];    # print "another value"

#2

The data param is supposed to be an object that has keys and values.

数据参数应该是具有键和值的对象。

var data = {
    hiddenContact: document.getElementById('hiddenContact').value
}
$.post('/callcenter/admin/postContacts', data);

Then in PHP you can retrieve it like this:

然后在PHP中，您可以像这样检索它：

$hiddenContact = $_POST["hiddenContact"];

I'm not a big CakePHP user but I believe the CakePHP version is like this:

我不是一个很大的CakePHP用户，但我相信CakePHP版本是这样的：

$hiddenContact = $this->params["hiddenContact"];

#3

//javascript
if(step==1)
{
   var data = {'MyFieldName':document.getElementById('hiddenContact').value};
   $.post('/callcenter/admin/postContacts', data, function(returnData){
      alert('The server said ' + returnData);
   });
}

//read the post in php
<?
   echo 'Your ajax post data was '. $_POST['MyFieldName'];
?>

#1