I'm doing a bash script and I'm grabbing the output from this command:
我正在做一个bash脚本,我正在抓取这个命令的输出:
fpings=$(fping -c 1 -t 1 $ips | sort)
The fpings variable does contain the output from the command, and the actual output of the command is not printed to the shell, but it still writes a line to the shell for each ip pinged.
fpings变量确实包含命令的输出,并且命令的实际输出不会打印到shell,但它仍会为每个ip ping的shell写一行。
There is a switch (-q) to suppress the output (the part that I want) but not any to suppress the part I don't want.
有一个开关(-q)来抑制输出(我想要的部分)但不能抑制我不想要的部分。
How do I get the result from the fpings command without it printing stuff to the shell?
如何在没有将内容打印到shell的情况下从fpings命令获取结果?
2 个解决方案
#1
6
If you do not want to see the standard error, redirect it to /dev/null:
如果您不想看到标准错误,请将其重定向到/ dev / null:
fpings=$(fping -c 1 -t 1 $ips 2>/dev/null | sort)
#2
2
fpings=$( {fping -c 1 -t 1 $ips | sort; } 2>&1 )
should work the {} capture everything and then it redirects both streams (out and err) to just out and saves in the variable
应该工作{}捕获所有内容然后它将两个流(out和err)重定向到刚出来并保存在变量中
#1
6
If you do not want to see the standard error, redirect it to /dev/null:
如果您不想看到标准错误,请将其重定向到/ dev / null:
fpings=$(fping -c 1 -t 1 $ips 2>/dev/null | sort)
#2
2
fpings=$( {fping -c 1 -t 1 $ips | sort; } 2>&1 )
should work the {} capture everything and then it redirects both streams (out and err) to just out and saves in the variable
应该工作{}捕获所有内容然后它将两个流(out和err)重定向到刚出来并保存在变量中