Let's say I have a json that looks like this:
假设我有一个看起来像这样的json:
some_json = {'key_a': {'nested_key': 'a'},
'key_b': {'nested_key': 'b'}}
Note that key_a
and key_b
are optional keys mapped to dictionaries and may or may not exist.
请注意,key_a和key_b是映射到字典的可选键,可能存在也可能不存在。
I have a function that checks if an outer key exists in some_json
and returns a boolean.
我有一个函数,检查some_json中是否存在外键并返回一个布尔值。
CREATE FUNCTION key_exists(some_json json, outer_key text)
RETURNS boolean AS $$
BEGIN
RETURN (some_json->outer_key IS NULL);
END;
$$ LANGUAGE plpgsql;
I get the following error:
我收到以下错误:
ProgrammingError: operator does not exist: json -> boolean
Why is outer_key
equating to a boolean? What's the proper syntax to perform this check?
为什么outer_key等于布尔值?执行此检查的正确语法是什么?
2 个解决方案
#1
13
Your function does the exact opposite of what the name is, but the way to fix your function is to add (
and )
around the some_json->outer_key
.
您的函数与名称完全相反,但修复函数的方法是在some_json-> outer_key周围添加(和)。
Here is it fully functioning, and matching the name of your function (notice the NOT
in front of the NULL
).
这是完全正常运行,并匹配您的函数名称(注意NULL前面的NOT)。
CREATE FUNCTION key_exists(some_json json, outer_key text)
RETURNS boolean AS $$
BEGIN
RETURN (some_json->outer_key) IS NOT NULL;
END;
$$ LANGUAGE plpgsql;
Some tests:
一些测试:
select key_exists('{"key_a": {"nested_key": "a"}, "key_b": {"nested_key": "b"}}'::json, 'key_a');
key_exists
------------
t
(1 row)
And here when a key doesn't exist:
在这里,当一个密钥不存在时:
select key_exists('{"key_a": {"nested_key": "a"}, "key_b": {"nested_key": "b"}}'::json, 'test');
key_exists
------------
f
(1 row)
#2
20
You can also use the '?' operator like that:
你也可以使用'?'这样的运算符:
SELECT '{"key_a":1}'::jsonb ? 'key_a'
And if you need to query by nested key, use like this:
如果您需要通过嵌套键进行查询,请使用如下:
SELECT '{"key_a": {"nested_key": "a"}}'::jsonb -> 'key_a' ? 'nested_key'
See http://www.postgresql.org/docs/9.5/static/functions-json.html
见http://www.postgresql.org/docs/9.5/static/functions-json.html
NOTE: Only for jsonb
type.
注意:仅适用于jsonb类型。
#1
13
Your function does the exact opposite of what the name is, but the way to fix your function is to add (
and )
around the some_json->outer_key
.
您的函数与名称完全相反,但修复函数的方法是在some_json-> outer_key周围添加(和)。
Here is it fully functioning, and matching the name of your function (notice the NOT
in front of the NULL
).
这是完全正常运行,并匹配您的函数名称(注意NULL前面的NOT)。
CREATE FUNCTION key_exists(some_json json, outer_key text)
RETURNS boolean AS $$
BEGIN
RETURN (some_json->outer_key) IS NOT NULL;
END;
$$ LANGUAGE plpgsql;
Some tests:
一些测试:
select key_exists('{"key_a": {"nested_key": "a"}, "key_b": {"nested_key": "b"}}'::json, 'key_a');
key_exists
------------
t
(1 row)
And here when a key doesn't exist:
在这里,当一个密钥不存在时:
select key_exists('{"key_a": {"nested_key": "a"}, "key_b": {"nested_key": "b"}}'::json, 'test');
key_exists
------------
f
(1 row)
#2
20
You can also use the '?' operator like that:
你也可以使用'?'这样的运算符:
SELECT '{"key_a":1}'::jsonb ? 'key_a'
And if you need to query by nested key, use like this:
如果您需要通过嵌套键进行查询,请使用如下:
SELECT '{"key_a": {"nested_key": "a"}}'::jsonb -> 'key_a' ? 'nested_key'
See http://www.postgresql.org/docs/9.5/static/functions-json.html
见http://www.postgresql.org/docs/9.5/static/functions-json.html
NOTE: Only for jsonb
type.
注意:仅适用于jsonb类型。