Rails 4中的单表继承

I'm trying to implement a somewhat simple STI in Rails 4, but there's something I can't yet manage to achieve.

我试图在Rails 4中实现一个有点简单的STI，但是有些东西我还没做到。

I have the following classes:

我有以下课程:

class Person < ActiveRecord::Base
end

class NaturalPerson < Person
end

class LegalPerson < Person
end

class Employee < NaturalPerson
end

class Customer < NaturalPerson
end

The thing is, I have some attributes that I want to access only from the Employee class, some only from Customer, etc, but I can't find the way. If I were to be using Rails 3's way I would've solved it with attr_accesible. But this isn't posible now, since I'm neither using the attr_accesible gem, nor I'm willing to.

问题是，我有一些只能从Employee类访问的属性，有些只能从Customer类访问，等等，但是我找不到方法。如果我使用Rails 3的方式，我将用attr_accesible解决它。但这并不是肯定的，因为我既没有使用诱人的宝石，也不愿意使用。

2 个解决方案

#1

I woud use different person_params in my controller,

我需要在我的控制器中使用不同的person_params，

def person_params
params.require(:person).permit(:email, :last_name, :first_name)
end

def natural_person_params
params.require(:person).permit(:email, :job, :location)
end

and create a method where I would test the class name of object or the type attribute as it is a STI) to determine which params to use...

并创建一个方法，在其中我将测试对象的类名或类型属性，因为它是一个STI)，以确定使用哪个params…

Hope this helps

希望这有助于

Cheers

干杯

#2

If you're trying to use a single controller for all of the models, then put ALL the attributes into the white listed params.

如果您试图为所有模型使用一个控制器，那么将所有属性放入白色列表的params中。

def person_params
  params.require(:person).permit(:email, :last_name, :first_name, :job, :location)
end

If you want to separate them, then you'll want separate params for each type of person:

如果你想把他们分开，那么你会想要每个类型的人都有不同的参数:

def person_params
  params.require(:person).permit(:email, :last_name, :first_name)
end

def employed_person_params
  params.require(:person).permit(:email, :job, :location)
end

#1