In Windows environment there is an API to obtain the path which is running a process. Is there something similar in Unix / Linux?
在Windows环境中,有一个API来获取运行进程的路径。在Unix / Linux中有类似的东西吗?
Or is there some other way to do that in these environments?
或者在这些环境中还有其他的方法吗?
10 个解决方案
#1
132
On Linux, the symlink /proc/<pid>/exe
has the path of the executable. Use the command readlink -f /proc/<pid>/exe
to get the value.
在Linux上,symlink /proc/
On AIX, this file does not exist. You could compare cksum <actual path to binary>
and cksum /proc/<pid>/object/a.out
.
在AIX上,这个文件不存在。您可以比较cksum <实际路径到二进制> 和cksum /proc/
#2
30
You can find the exe easily by these ways, just try it yourself.
你可以通过这些方法轻松找到exe,你可以自己尝试一下。
ll /proc/<PID>/exe
- /proc/< PID > / exe
pwdx <PID>
- pwdx < PID >
lsof -p <PID> | grep cwd
-
lsof -p
| grep cwd
#3
26
EDITORS NOTE The code below has a bug. readlink
does not null terminate the output string, so if it works, it was an accident.
编辑注意到下面的代码有一个错误。readlink不为空终止输出字符串,因此如果它工作,这是一个意外。
A little bit late, but all the answers were specific to linux.
有点晚了,但是所有的答案都是针对linux的。
If you need also unix, then you need this:
如果您还需要unix,那么您需要:
char * getExecPath (char * path,size_t dest_len, char * argv0)
{
char * baseName = NULL;
char * systemPath = NULL;
char * candidateDir = NULL;
/* the easiest case: we are in linux */
if (readlink ("/proc/self/exe", path, dest_len) != -1)
{
dirname (path);
strcat (path, "/");
return path;
}
/* Ups... not in linux, no guarantee */
/* check if we have something like execve("foobar", NULL, NULL) */
if (argv0 == NULL)
{
/* we surrender and give current path instead */
if (getcwd (path, dest_len) == NULL) return NULL;
strcat (path, "/");
return path;
}
/* argv[0] */
/* if dest_len < PATH_MAX may cause buffer overflow */
if ((realpath (argv0, path)) && (!access (path, F_OK)))
{
dirname (path);
strcat (path, "/");
return path;
}
/* Current path */
baseName = basename (argv0);
if (getcwd (path, dest_len - strlen (baseName) - 1) == NULL)
return NULL;
strcat (path, "/");
strcat (path, baseName);
if (access (path, F_OK) == 0)
{
dirname (path);
strcat (path, "/");
return path;
}
/* Try the PATH. */
systemPath = getenv ("PATH");
if (systemPath != NULL)
{
dest_len--;
systemPath = strdup (systemPath);
for (candidateDir = strtok (systemPath, ":"); candidateDir != NULL; candidateDir = strtok (NULL, ":"))
{
strncpy (path, candidateDir, dest_len);
strncat (path, "/", dest_len);
strncat (path, baseName, dest_len);
if (access(path, F_OK) == 0)
{
free (systemPath);
dirname (path);
strcat (path, "/");
return path;
}
}
free(systemPath);
dest_len++;
}
/* again someone has use execve: we dont knowe the executable name; we surrender and give instead current path */
if (getcwd (path, dest_len - 1) == NULL) return NULL;
strcat (path, "/");
return path;
}
#4
9
I use:
我使用:
ps -ef | grep 786
Replace 786 with your PID or process name.
用PID或进程名替换786。
#5
4
In Linux every process has its own folder in /proc
. So you could use getpid()
to get the pid of the running process and then join it with the path /proc
to get the folder you hopefully need.
在Linux中,每个进程在/proc中都有自己的文件夹。因此,您可以使用getpid()获取正在运行的进程的pid,然后将其与path /proc结合,以获得您希望需要的文件夹。
Here's a short example in Python:
下面是Python的一个简短示例:
import os
print os.path.join('/proc', str(os.getpid()))
Here's the example in ANSI C as well:
这里还有一个ANSI C的例子:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
int
main(int argc, char **argv)
{
pid_t pid = getpid();
fprintf(stdout, "Path to current process: '/proc/%d/'\n", (int)pid);
return EXIT_SUCCESS;
}
Compile it with:
编译:
gcc -Wall -Werror -g -ansi -pedantic process_path.c -oprocess_path
#6
2
There's no "guaranteed to work anywhere" method.
没有“保证在任何地方工作”的方法。
Step 1 is to check argv[0], if the program was started by its full path, this would (usually) have the full path. If it was started by a relative path, the same holds (though this requires getting teh current working directory, using getcwd().
第一步是检查argv[0],如果程序是由它的完整路径启动的,那么它(通常)将拥有完整的路径。如果它是由一个相对路径启动的,则保持不变(尽管这需要使用getcwd()获取当前工作目录。
Step 2, if none of the above holds, is to get the name of the program, then get the name of the program from argv[0], then get the user's PATH from the environment and go through that to see if there's a suitable executable binary with the same name.
第2步,如果上面这些都不成立,那么获取程序的名称,然后从argv[0]获取程序的名称,然后从环境中获取用户的路径,然后遍历该路径,看看是否有一个合适的、同名的可执行二进制文件。
Note that argv[0] is set by the process that execs the program, so it is not 100% reliable.
请注意,argv[0]是由执行程序的进程设置的,因此它不是100%可靠的。
#7
2
thanks : Kiwy
with AIX:
谢谢:Kiwy与AIX:
getPathByPid()
{
if [[ -e /proc/$1/object/a.out ]]; then
inode=`ls -i /proc/$1/object/a.out 2>/dev/null | awk '{print $1}'`
if [[ $? -eq 0 ]]; then
strnode=${inode}"$"
strNum=`ls -li /proc/$1/object/ 2>/dev/null | grep $strnode | awk '{print $NF}' | grep "[0-9]\{1,\}\.[0-9]\{1,\}\."`
if [[ $? -eq 0 ]]; then
# jfs2.10.6.5869
n1=`echo $strNum|awk -F"." '{print $2}'`
n2=`echo $strNum|awk -F"." '{print $3}'`
# brw-rw---- 1 root system 10, 6 Aug 23 2013 hd9var
strexp="^b.*"$n1,"[[:space:]]\{1,\}"$n2"[[:space:]]\{1,\}.*$" # "^b.*10, \{1,\}5 \{1,\}.*$"
strdf=`ls -l /dev/ | grep $strexp | awk '{print $NF}'`
if [[ $? -eq 0 ]]; then
strMpath=`df | grep $strdf | awk '{print $NF}'`
if [[ $? -eq 0 ]]; then
find $strMpath -inum $inode 2>/dev/null
if [[ $? -eq 0 ]]; then
return 0
fi
fi
fi
fi
fi
fi
return 1
}
#8
2
pwdx <process id>
pwdx <进程id>
This command will fetch the process path from where it is executing.
该命令将从正在执行的地方获取进程路径。
#9
1
You can also get the path on GNU/Linux with (not thoroughly tested):
您还可以使用(未经过彻底测试)的GNU/Linux路径:
char file[32];
char buf[64];
pid_t pid = getpid();
sprintf(file, "/proc/%i/cmdline", pid);
FILE *f = fopen(file, "r");
fgets(buf, 64, f);
fclose(f);
If you want the directory of the executable for perhaps changing the working directory to the process's directory (for media/data/etc), you need to drop everything after the last /:
如果您想要可执行文件的目录将工作目录更改为进程的目录(用于媒体/数据/等),您需要在最后/:
*strrchr(buf, '/') = '\0';
/*chdir(buf);*/
#10
-1
Find the path to a process name
找到进程名的路径
#!/bin/bash
# @author Lukas Gottschall
PID=`ps aux | grep precessname | grep -v grep | awk '{ print $2 }'`
PATH=`ls -ald --color=never /proc/$PID/exe | awk '{ print $10 }'`
echo $PATH
#1
132
On Linux, the symlink /proc/<pid>/exe
has the path of the executable. Use the command readlink -f /proc/<pid>/exe
to get the value.
在Linux上,symlink /proc/
On AIX, this file does not exist. You could compare cksum <actual path to binary>
and cksum /proc/<pid>/object/a.out
.
在AIX上,这个文件不存在。您可以比较cksum <实际路径到二进制> 和cksum /proc/
#2
30
You can find the exe easily by these ways, just try it yourself.
你可以通过这些方法轻松找到exe,你可以自己尝试一下。
ll /proc/<PID>/exe
- /proc/< PID > / exe
pwdx <PID>
- pwdx < PID >
lsof -p <PID> | grep cwd
-
lsof -p
| grep cwd
#3
26
EDITORS NOTE The code below has a bug. readlink
does not null terminate the output string, so if it works, it was an accident.
编辑注意到下面的代码有一个错误。readlink不为空终止输出字符串,因此如果它工作,这是一个意外。
A little bit late, but all the answers were specific to linux.
有点晚了,但是所有的答案都是针对linux的。
If you need also unix, then you need this:
如果您还需要unix,那么您需要:
char * getExecPath (char * path,size_t dest_len, char * argv0)
{
char * baseName = NULL;
char * systemPath = NULL;
char * candidateDir = NULL;
/* the easiest case: we are in linux */
if (readlink ("/proc/self/exe", path, dest_len) != -1)
{
dirname (path);
strcat (path, "/");
return path;
}
/* Ups... not in linux, no guarantee */
/* check if we have something like execve("foobar", NULL, NULL) */
if (argv0 == NULL)
{
/* we surrender and give current path instead */
if (getcwd (path, dest_len) == NULL) return NULL;
strcat (path, "/");
return path;
}
/* argv[0] */
/* if dest_len < PATH_MAX may cause buffer overflow */
if ((realpath (argv0, path)) && (!access (path, F_OK)))
{
dirname (path);
strcat (path, "/");
return path;
}
/* Current path */
baseName = basename (argv0);
if (getcwd (path, dest_len - strlen (baseName) - 1) == NULL)
return NULL;
strcat (path, "/");
strcat (path, baseName);
if (access (path, F_OK) == 0)
{
dirname (path);
strcat (path, "/");
return path;
}
/* Try the PATH. */
systemPath = getenv ("PATH");
if (systemPath != NULL)
{
dest_len--;
systemPath = strdup (systemPath);
for (candidateDir = strtok (systemPath, ":"); candidateDir != NULL; candidateDir = strtok (NULL, ":"))
{
strncpy (path, candidateDir, dest_len);
strncat (path, "/", dest_len);
strncat (path, baseName, dest_len);
if (access(path, F_OK) == 0)
{
free (systemPath);
dirname (path);
strcat (path, "/");
return path;
}
}
free(systemPath);
dest_len++;
}
/* again someone has use execve: we dont knowe the executable name; we surrender and give instead current path */
if (getcwd (path, dest_len - 1) == NULL) return NULL;
strcat (path, "/");
return path;
}
#4
9
I use:
我使用:
ps -ef | grep 786
Replace 786 with your PID or process name.
用PID或进程名替换786。
#5
4
In Linux every process has its own folder in /proc
. So you could use getpid()
to get the pid of the running process and then join it with the path /proc
to get the folder you hopefully need.
在Linux中,每个进程在/proc中都有自己的文件夹。因此,您可以使用getpid()获取正在运行的进程的pid,然后将其与path /proc结合,以获得您希望需要的文件夹。
Here's a short example in Python:
下面是Python的一个简短示例:
import os
print os.path.join('/proc', str(os.getpid()))
Here's the example in ANSI C as well:
这里还有一个ANSI C的例子:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
int
main(int argc, char **argv)
{
pid_t pid = getpid();
fprintf(stdout, "Path to current process: '/proc/%d/'\n", (int)pid);
return EXIT_SUCCESS;
}
Compile it with:
编译:
gcc -Wall -Werror -g -ansi -pedantic process_path.c -oprocess_path
#6
2
There's no "guaranteed to work anywhere" method.
没有“保证在任何地方工作”的方法。
Step 1 is to check argv[0], if the program was started by its full path, this would (usually) have the full path. If it was started by a relative path, the same holds (though this requires getting teh current working directory, using getcwd().
第一步是检查argv[0],如果程序是由它的完整路径启动的,那么它(通常)将拥有完整的路径。如果它是由一个相对路径启动的,则保持不变(尽管这需要使用getcwd()获取当前工作目录。
Step 2, if none of the above holds, is to get the name of the program, then get the name of the program from argv[0], then get the user's PATH from the environment and go through that to see if there's a suitable executable binary with the same name.
第2步,如果上面这些都不成立,那么获取程序的名称,然后从argv[0]获取程序的名称,然后从环境中获取用户的路径,然后遍历该路径,看看是否有一个合适的、同名的可执行二进制文件。
Note that argv[0] is set by the process that execs the program, so it is not 100% reliable.
请注意,argv[0]是由执行程序的进程设置的,因此它不是100%可靠的。
#7
2
thanks : Kiwy
with AIX:
谢谢:Kiwy与AIX:
getPathByPid()
{
if [[ -e /proc/$1/object/a.out ]]; then
inode=`ls -i /proc/$1/object/a.out 2>/dev/null | awk '{print $1}'`
if [[ $? -eq 0 ]]; then
strnode=${inode}"$"
strNum=`ls -li /proc/$1/object/ 2>/dev/null | grep $strnode | awk '{print $NF}' | grep "[0-9]\{1,\}\.[0-9]\{1,\}\."`
if [[ $? -eq 0 ]]; then
# jfs2.10.6.5869
n1=`echo $strNum|awk -F"." '{print $2}'`
n2=`echo $strNum|awk -F"." '{print $3}'`
# brw-rw---- 1 root system 10, 6 Aug 23 2013 hd9var
strexp="^b.*"$n1,"[[:space:]]\{1,\}"$n2"[[:space:]]\{1,\}.*$" # "^b.*10, \{1,\}5 \{1,\}.*$"
strdf=`ls -l /dev/ | grep $strexp | awk '{print $NF}'`
if [[ $? -eq 0 ]]; then
strMpath=`df | grep $strdf | awk '{print $NF}'`
if [[ $? -eq 0 ]]; then
find $strMpath -inum $inode 2>/dev/null
if [[ $? -eq 0 ]]; then
return 0
fi
fi
fi
fi
fi
fi
return 1
}
#8
2
pwdx <process id>
pwdx <进程id>
This command will fetch the process path from where it is executing.
该命令将从正在执行的地方获取进程路径。
#9
1
You can also get the path on GNU/Linux with (not thoroughly tested):
您还可以使用(未经过彻底测试)的GNU/Linux路径:
char file[32];
char buf[64];
pid_t pid = getpid();
sprintf(file, "/proc/%i/cmdline", pid);
FILE *f = fopen(file, "r");
fgets(buf, 64, f);
fclose(f);
If you want the directory of the executable for perhaps changing the working directory to the process's directory (for media/data/etc), you need to drop everything after the last /:
如果您想要可执行文件的目录将工作目录更改为进程的目录(用于媒体/数据/等),您需要在最后/:
*strrchr(buf, '/') = '\0';
/*chdir(buf);*/
#10
-1
Find the path to a process name
找到进程名的路径
#!/bin/bash
# @author Lukas Gottschall
PID=`ps aux | grep precessname | grep -v grep | awk '{ print $2 }'`
PATH=`ls -ald --color=never /proc/$PID/exe | awk '{ print $10 }'`
echo $PATH