bash脚本将grep count赋给变量

How to assign the result of
grep -c "some text" /tmp/somePath
into variable so I can echo it.
Thanks!

如何将grep -c“some text”/ tmp / somePath的结果分配给变量，以便我可以回应它。谢谢！

#!/bin/bash
some_var = grep -c "some text" /tmp/somePath
echo "var value is: ${some_var}"

I also tried: some_var = 'grep -c \"some text\" /tmp/somePath'

我也尝试过：some_var ='grep -c \“some text \”/ tmp / somePath'

But I keep getting: command not found

但我一直得到：没找到命令

Thanks

谢谢

3 个解决方案

#1

To assign the output of a command, use var=$(cmd) (as shellcheck automatically tells you if you paste your script there).

要分配命令的输出，请使用var = $（cmd）（因为shellcheck会自动告诉您是否将脚本粘贴到那里）。

#!/bin/bash
some_var=$(grep -c "some text" /tmp/somePath)
echo "var value is: ${some_var}"

#2

Found the issue
Its the assignment, this will work:

找到问题它的任务，这将工作：

some_var=$(command)

While this won't work:

虽然这不起作用：

some_var = $(command)

Thank you for your help! I will accept first helpful answer.

感谢您的帮助！我会接受第一个有用的答案。

#3

some_var=$(grep -c "some text" /tmp/somePath)

From man bash:

来自man bash：

   Command substitution allows the output of a command to replace the com‐
   mand name.  There are two forms:

          $(command)
   or
          `command`

   Bash performs the expansion by executing command and replacing the com‐
   mand substitution with the standard output of  the  command,  with  any
   trailing newlines deleted.

#1