I am developing an application. One of the methods needs to capture the computer name and user logged on the machine, then display both to the user. I need it to run on both Windows and Linux. What is the best way to do this?
我正在开发一个应用程序。其中一种方法需要捕获计算机名和登录到计算机上的用户,然后将这两种方法都显示给用户。我需要它在Windows和Linux上运行。最好的方法是什么?
6 个解决方案
#1
15
Windows
窗户
You can try to use GetComputerName
and GetUserName
, here is a example:
您可以尝试使用GetComputerName和GetUserName,这里有一个例子:
#define INFO_BUFFER_SIZE 32767
TCHAR infoBuf[INFO_BUFFER_SIZE];
DWORD bufCharCount = INFO_BUFFER_SIZE;
// Get and display the name of the computer.
if( !GetComputerName( infoBuf, &bufCharCount ) )
printError( TEXT("GetComputerName") );
_tprintf( TEXT("\nComputer name: %s"), infoBuf );
// Get and display the user name.
if( !GetUserName( infoBuf, &bufCharCount ) )
printError( TEXT("GetUserName") );
_tprintf( TEXT("\nUser name: %s"), infoBuf );
see: GetComputerName and GetUserName
看:GetComputerName GetUserName
Linux
Linux
Use gethostname
to get computer name(see gethostname), and getlogin_r
to get login username. You can look more information at man page of getlogin_r. Simple usage as follows:
使用gethostname获取计算机名(参见gethostname),使用getlogin_r获取登录用户名。您可以在getlogin_r的man页面查看更多信息。简单的用法如下:
#include <unistd.h>
#include <limits.h>
char hostname[HOST_NAME_MAX];
char username[LOGIN_NAME_MAX];
gethostname(hostname, HOST_NAME_MAX);
getlogin_r(username, LOGIN_NAME_MAX);
#2
8
On POSIX systems you can use the gethostname
and getlogin
functions, both declared in unistd.h
.
在POSIX系统上,可以使用gethostname和getlogin函数,这两个函数都在unistd.h中声明。
/*
This is a C program (I've seen the C++ tag too late). Converting
it to a pretty C++ program is left as an exercise to the reader.
*/
#include <limits.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int
main()
{
char hostname[HOST_NAME_MAX];
char username[LOGIN_NAME_MAX];
int result;
result = gethostname(hostname, HOST_NAME_MAX);
if (result)
{
perror("gethostname");
return EXIT_FAILURE;
}
result = getlogin_r(username, LOGIN_NAME_MAX);
if (result)
{
perror("getlogin_r");
return EXIT_FAILURE;
}
result = printf("Hello %s, you are logged in to %s.\n",
username, hostname);
if (result < 0)
{
perror("printf");
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
Possible output:
可能的输出:
Hello 5gon12eder, you are logged in to example.com.
This seems safer than relying on environment variables which are not always present.
这似乎比依赖不总是存在的环境变量更安全。
I'm withdrawing that last statement because
我撤回最后一个声明是因为
- the man page of
getlogin
actually discourages its usage in favour ofgetenv("LOGIN")
and - getlogin的man页面实际上不鼓励使用getenv(“LOGIN”)和
- the
getlogin_r
call in the above program fails withENOTTY
when I run the program from within Emacs instead of an interactive terminal whilegetenv("USER")
would have worked in both situations. - 当我在Emacs中运行程序而不是交互式终端时,上面的getlogin_r调用失败了,而getenv(“用户”)在这两种情况下都能工作。
#3
7
In Windows environment you can use getenv("COMPUTERNAME")
, getenv("USERNAME")
In Linux - getenv("HOSTNAME")
, getenv("USER")
在Windows环境中,您可以使用getenv(“COMPUTERNAME”)、getenv(“USERNAME”)、getenv(“HOSTNAME”)、getenv(“USER”)
See getenv reference
看到getenv参考
#4
7
If you can use Boost, you can do this to easily get the host name:
如果您可以使用Boost,您可以这样做来轻松获取主机名:
#include <boost/asio/ip/host_name.hpp>
// ... whatever ...
auto host_name = boost::asio::ip::host_name();
#5
#6
3
Regarding Denis's answer, note that getenv("HOSTNAME")
for Linux may not always work because the environment variables may not be exported to the program.
关于Denis的回答,请注意Linux的getenv(“HOSTNAME”)可能并不总是有效,因为环境变量可能不会被导出到程序中。
Multi-platform C++ code example to fetch just the computer name (this is what worked for my Win7 and CentOS machines):
多平台c++代码示例,只获取计算机名(这是我的Win7和CentOS计算机的工作原理):
char *temp = 0;
std::string computerName;
#if defined(WIN32) || defined(_WIN32) || defined(_WIN64)
temp = getenv("COMPUTERNAME");
if (temp != 0) {
computerName = temp;
temp = 0;
}
#else
temp = getenv("HOSTNAME");
if (temp != 0) {
computerName = temp;
temp = 0;
} else {
temp = new char[512];
if (gethostbyname(temp, 512) == 0) { // success = 0, failure = -1
computerName = temp;
}
delete []temp;
temp = 0;
}
#endif
#1
15
Windows
窗户
You can try to use GetComputerName
and GetUserName
, here is a example:
您可以尝试使用GetComputerName和GetUserName,这里有一个例子:
#define INFO_BUFFER_SIZE 32767
TCHAR infoBuf[INFO_BUFFER_SIZE];
DWORD bufCharCount = INFO_BUFFER_SIZE;
// Get and display the name of the computer.
if( !GetComputerName( infoBuf, &bufCharCount ) )
printError( TEXT("GetComputerName") );
_tprintf( TEXT("\nComputer name: %s"), infoBuf );
// Get and display the user name.
if( !GetUserName( infoBuf, &bufCharCount ) )
printError( TEXT("GetUserName") );
_tprintf( TEXT("\nUser name: %s"), infoBuf );
see: GetComputerName and GetUserName
看:GetComputerName GetUserName
Linux
Linux
Use gethostname
to get computer name(see gethostname), and getlogin_r
to get login username. You can look more information at man page of getlogin_r. Simple usage as follows:
使用gethostname获取计算机名(参见gethostname),使用getlogin_r获取登录用户名。您可以在getlogin_r的man页面查看更多信息。简单的用法如下:
#include <unistd.h>
#include <limits.h>
char hostname[HOST_NAME_MAX];
char username[LOGIN_NAME_MAX];
gethostname(hostname, HOST_NAME_MAX);
getlogin_r(username, LOGIN_NAME_MAX);
#2
8
On POSIX systems you can use the gethostname
and getlogin
functions, both declared in unistd.h
.
在POSIX系统上,可以使用gethostname和getlogin函数,这两个函数都在unistd.h中声明。
/*
This is a C program (I've seen the C++ tag too late). Converting
it to a pretty C++ program is left as an exercise to the reader.
*/
#include <limits.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int
main()
{
char hostname[HOST_NAME_MAX];
char username[LOGIN_NAME_MAX];
int result;
result = gethostname(hostname, HOST_NAME_MAX);
if (result)
{
perror("gethostname");
return EXIT_FAILURE;
}
result = getlogin_r(username, LOGIN_NAME_MAX);
if (result)
{
perror("getlogin_r");
return EXIT_FAILURE;
}
result = printf("Hello %s, you are logged in to %s.\n",
username, hostname);
if (result < 0)
{
perror("printf");
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
Possible output:
可能的输出:
Hello 5gon12eder, you are logged in to example.com.
This seems safer than relying on environment variables which are not always present.
这似乎比依赖不总是存在的环境变量更安全。
I'm withdrawing that last statement because
我撤回最后一个声明是因为
- the man page of
getlogin
actually discourages its usage in favour ofgetenv("LOGIN")
and - getlogin的man页面实际上不鼓励使用getenv(“LOGIN”)和
- the
getlogin_r
call in the above program fails withENOTTY
when I run the program from within Emacs instead of an interactive terminal whilegetenv("USER")
would have worked in both situations. - 当我在Emacs中运行程序而不是交互式终端时,上面的getlogin_r调用失败了,而getenv(“用户”)在这两种情况下都能工作。
#3
7
In Windows environment you can use getenv("COMPUTERNAME")
, getenv("USERNAME")
In Linux - getenv("HOSTNAME")
, getenv("USER")
在Windows环境中,您可以使用getenv(“COMPUTERNAME”)、getenv(“USERNAME”)、getenv(“HOSTNAME”)、getenv(“USER”)
See getenv reference
看到getenv参考
#4
7
If you can use Boost, you can do this to easily get the host name:
如果您可以使用Boost,您可以这样做来轻松获取主机名:
#include <boost/asio/ip/host_name.hpp>
// ... whatever ...
auto host_name = boost::asio::ip::host_name();
#5
3
Use gethostname()
to get computer name, support both windows and linux.
使用gethostname()获取计算机名,支持windows和linux。
#6
3
Regarding Denis's answer, note that getenv("HOSTNAME")
for Linux may not always work because the environment variables may not be exported to the program.
关于Denis的回答,请注意Linux的getenv(“HOSTNAME”)可能并不总是有效,因为环境变量可能不会被导出到程序中。
Multi-platform C++ code example to fetch just the computer name (this is what worked for my Win7 and CentOS machines):
多平台c++代码示例,只获取计算机名(这是我的Win7和CentOS计算机的工作原理):
char *temp = 0;
std::string computerName;
#if defined(WIN32) || defined(_WIN32) || defined(_WIN64)
temp = getenv("COMPUTERNAME");
if (temp != 0) {
computerName = temp;
temp = 0;
}
#else
temp = getenv("HOSTNAME");
if (temp != 0) {
computerName = temp;
temp = 0;
} else {
temp = new char[512];
if (gethostbyname(temp, 512) == 0) { // success = 0, failure = -1
computerName = temp;
}
delete []temp;
temp = 0;
}
#endif