使用带静态的函数C编程华氏度到摄氏度的错误转换

So I'm writing a fun program that converts celsius to Fahrenheit and I'm using a function with static. My current code looks like this and I basically want to know the error here because beside the first column of numbers all the numbers appear to be 2686824.

所以我正在写一个有趣的程序,将摄氏温度转换为华氏温度,我正在使用静态函数。我当前的代码看起来像这样,我基本上想知道这里的错误,因为在第一列数字旁边,所有数字看起来都是2686824。

#include <stdio.h>

int table(int fahr, int celsius) {
    static int total = 0;
    total += fahr;
    total += celsius;
    return total;
}

int main () {

   int i;
   int n = 20;
   int conversion = (n-32) * (5/9);
   printf("Temperature conversion program\n");

   for(i = 0; i < 20; i++) {
      printf("%d %6d\n", table(n, conversion));
   }
}

2 个解决方案

#1

your program does not convert anything. It just adds the both values.

你的程序没有转换任何东西。它只是添加了两个值。

#include <stdio.h>

double toCelc(double fahr)
{
    return (fahr - 32.0) * (5.0/9.0); 
}

double toFahr(double celc)
{
    return celc * 9.0 / 5.0 + 32.0;
}


int main()
{
    for(int c = -30; c < 40; c++)
    {
        printf("F: %.2f\t\tC:%.2f\n", toFahr(c), (double)c);
    }

    for(int f = -30; f < 100; f++)
    {
        printf("F: %.2f\t\tC:%.2f\n", (double)f, toCelc(f));
    }


    return 0;
}

#2

You calculate only one time

你只计算一次

int conversion = (n-32) * (5/9);

and n is always 20

而且n总是20

table(n, conversion)

So its always the same parameter

所以它始终是相同的参数

#1