Is there a way to specify a gulp task depending on the NODE_ENV
that is set?
有没有办法根据设置的NODE_ENV指定gulp任务?
For example in my package.json
file, I have something like:
例如在我的package.json文件中,我有类似的东西:
"scripts": {
"start": "gulp"
}
And I have multiple gulp
tasks
我有多个gulp任务
gulp.task('development', function () {
// run dev related tasks like watch
});
gulp.task('production', function () {
// run prod related tasks
});
If I set NODE_ENV=production npm start
, can I specify to only run gulp production
? Or is there a better way to do this?
如果我设置NODE_ENV =生产npm start,我可以指定只运行gulp生产吗?或者有更好的方法吗?
4 个解决方案
#1
13
Using a single ternary in your default gulp task, you can have something like:
在默认的gulp任务中使用单个三元组,您可以使用以下内容:
gulp.task('default',
[process.env.NODE_ENV === 'production' ? 'production' : 'development']
);
You will then be able to keep the single gulp
command in your package.json
and using this like you said:
然后,您将能够在package.json中保留单个gulp命令,并像您说的那样使用它:
NODE_ENV=production npm start
Any other value of your NODE_ENV
variable will launch the development
task.
NODE_ENV变量的任何其他值都将启动开发任务。
You could of course do an advanced usage using an object allowing for multiple tasks and avoiding if
trees hell:
您当然可以使用允许多个任务的对象进行高级使用,并避免树木地狱:
var tasks = {
development: 'development',
production: ['git', 'build', 'publish'],
preprod: ['build:preprod', 'publish:preprod'],
...
}
gulp.task('default', tasks[process.env.NODE_ENV] || 'fallback')
Keep in mind that when giving an array of tasks, they will be run in parallel.
请记住,在提供一系列任务时,它们将并行运行。
#2
2
Have your first gulp task run other gulp tasks based on the process.env.NODE_ENV
value.
让您的第一个gulp任务根据process.env.NODE_ENV值运行其他gulp任务。
gulp.task('launcher', function(){
switch (process.env.NODE_ENV){
case 'development':
// Run dev tasks from here
break;
case 'production':
// Run prod tasks
break;
}
});
#3
1
The other simple way could be
另一种简单的方法可能是
gulp.task('set-dev-env', function () {
return process.env.NODE_ENV = 'development';
});
gulp.task('set-prod-env', function () {
return process.env.NODE_ENV = 'production';
});
gulp.task('development', ['set-dev-env'], function () {
// your code
});
gulp.task('production', ['set-prod-env'], function () {
// your code
});
Run gulp production
or gulp development
.
运行gulp生产或gulp开发。
#4
-3
if (process.env.NODE_ENV === "production")
// whatever
#1
13
Using a single ternary in your default gulp task, you can have something like:
在默认的gulp任务中使用单个三元组,您可以使用以下内容:
gulp.task('default',
[process.env.NODE_ENV === 'production' ? 'production' : 'development']
);
You will then be able to keep the single gulp
command in your package.json
and using this like you said:
然后,您将能够在package.json中保留单个gulp命令,并像您说的那样使用它:
NODE_ENV=production npm start
Any other value of your NODE_ENV
variable will launch the development
task.
NODE_ENV变量的任何其他值都将启动开发任务。
You could of course do an advanced usage using an object allowing for multiple tasks and avoiding if
trees hell:
您当然可以使用允许多个任务的对象进行高级使用,并避免树木地狱:
var tasks = {
development: 'development',
production: ['git', 'build', 'publish'],
preprod: ['build:preprod', 'publish:preprod'],
...
}
gulp.task('default', tasks[process.env.NODE_ENV] || 'fallback')
Keep in mind that when giving an array of tasks, they will be run in parallel.
请记住,在提供一系列任务时,它们将并行运行。
#2
2
Have your first gulp task run other gulp tasks based on the process.env.NODE_ENV
value.
让您的第一个gulp任务根据process.env.NODE_ENV值运行其他gulp任务。
gulp.task('launcher', function(){
switch (process.env.NODE_ENV){
case 'development':
// Run dev tasks from here
break;
case 'production':
// Run prod tasks
break;
}
});
#3
1
The other simple way could be
另一种简单的方法可能是
gulp.task('set-dev-env', function () {
return process.env.NODE_ENV = 'development';
});
gulp.task('set-prod-env', function () {
return process.env.NODE_ENV = 'production';
});
gulp.task('development', ['set-dev-env'], function () {
// your code
});
gulp.task('production', ['set-prod-env'], function () {
// your code
});
Run gulp production
or gulp development
.
运行gulp生产或gulp开发。
#4
-3
if (process.env.NODE_ENV === "production")
// whatever