I have the following type:
我有以下类型:
data SomeType = Var String
deriving (Eq,Show)
newtype TypeA = TypeA [(String, SomeType)]
deriving (Eq,Show)
Also, I have a function:
另外,我有一个功能:
fun1 :: TypeA -> TypeA -> TypeA
I can use this function for mappend
.
我可以将此功能用于mappend。
I don't understand, how to implement Monoid interface in my case.
我不明白,在我的情况下如何实现Monoid接口。
1 个解决方案
#1
If you already have fun1
, just add an instance:
如果你已经有了fun1,只需添加一个实例:
instance Monoid TypeA where
mempty = .... -- fill this with the neutral element
mappend = fun1
Probably, you want mempty = TypeA []
.
可能,你想要mempty = TypeA []。
#1
If you already have fun1
, just add an instance:
如果你已经有了fun1,只需添加一个实例:
instance Monoid TypeA where
mempty = .... -- fill this with the neutral element
mappend = fun1
Probably, you want mempty = TypeA []
.
可能,你想要mempty = TypeA []。