Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
Solution 1:recursion,the key is to find out all situations of return true and false
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
if(!p && !q)return true;
if(p && !q)return false;
if(!p && q)return false;
if(isSameTree(p->left, q->left) && isSameTree(p->right, q->right) && p->val==q->val)return true;
return false; }
};
Solution 2: 非递归,待续