window下获取指定目录下面的所有文件名 c/c++

摘自：http://blog.csdn.net/gengoo/article/details/4622084?reload

#include <iostream>
#include <string>
#include <io.h>
using namespace std;

void main(int argc, char **argv)
{
 _finddata_t file;
 long longf;

 //_findfirst返回的是long型; long __cdecl _findfirst(const char *, struct _finddata_t *)
 if((longf = _findfirst("d://*.*", &file))==-1l)
 {
  cout<<"文件没有找到!/n";
 }
 else
 {
  cout<<"/n文件列表:/n";
  //int __cdecl _findnext(long, struct _finddata_t *);如果找到下个文件的名字成功的话就返回0,否则返回-1
  string tempName;
  while( _findnext( longf, &file ) == 0 )
  {
   tempName = "";
   tempName = file.name;
   if (tempName == "..")
   {
    continue;
   }

   cout<<file.name;

   if(file.attrib == _A_NORMAL)
   {
    cout<<"  普通文件  ";
   }
   else if(file.attrib == _A_RDONLY)
   {
    cout<<"  只读文件  ";
   }
   else if(file.attrib == _A_HIDDEN )
   {
    cout<<"  隐藏文件  ";
   }
   else if(file.attrib == _A_SYSTEM )
   {
    cout<<"  系统文件  ";
   }
   else if(file.attrib == _A_SUBDIR)
   {
    cout<<"  子目录  ";
   }
   else
   {
    cout<<"  存档文件  ";
   }
   cout<<endl;
  }
 }

 _findclose(longf);

}