[BZOJ 3282] Tree 【LCT】

时间:2021-04-05 21:08:28

题目链接:BZOJ - 3282

题目分析

这道题是裸的LCT,包含 Link , Cut 和询问两点之间的路径信息。

写代码时出现的错误:Access(x) 的循环中应该切断的是原来的 Son[x][1] ,然而我写成了 Son[x][0] !

代码

#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm> using namespace std; inline void Read(int &Num)
{
char c = getchar();
bool Neg = false;
while (c < '0' || c > '9')
{
if (c == '-') Neg = true;
c = getchar();
}
Num = c - '0'; c = getchar();
while (c >= '0' && c <= '9')
{
Num = Num * 10 + c - '0';
c = getchar();
}
if (Neg) Num = -Num;
} const int MaxN = 300000 + 5; int n, m;
int A[MaxN], T[MaxN], Father[MaxN], Son[MaxN][2]; bool isRoot[MaxN], Rev[MaxN]; inline void Update(int x)
{
T[x] = T[Son[x][0]] ^ T[Son[x][1]] ^ A[x];
} inline void Reverse(int x)
{
Rev[x] = !Rev[x];
swap(Son[x][0], Son[x][1]);
} inline void PushDown(int x)
{
if (!Rev[x]) return;
Rev[x] = false;
if (Son[x][0]) Reverse(Son[x][0]);
if (Son[x][1]) Reverse(Son[x][1]);
} void Rotate(int x)
{
int y = Father[x], f;
PushDown(y); PushDown(x);
if (x == Son[y][0]) f = 1;
else f = 0;
if (isRoot[y])
{
isRoot[y] = false;
isRoot[x] = true;
}
else
{
if (y == Son[Father[y]][0]) Son[Father[y]][0] = x;
else Son[Father[y]][1] = x;
}
Father[x] = Father[y];
Son[y][f ^ 1] = Son[x][f];
if (Son[x][f]) Father[Son[x][f]] = y;
Son[x][f] = y;
Father[y] = x;
Update(y);
Update(x);
} void Splay(int x)
{
int y;
while (!isRoot[x])
{
y = Father[x];
if (isRoot[y])
{
Rotate(x);
break;
}
if (y == Son[Father[y]][0])
{
if (x == Son[y][0])
{
Rotate(y);
Rotate(x);
}
else
{
Rotate(x);
Rotate(x);
}
}
else
{
if (x == Son[y][1])
{
Rotate(y);
Rotate(x);
}
else
{
Rotate(x);
Rotate(x);
}
}
}
} int Access(int x)
{
int y = 0;
while (x != 0)
{
Splay(x);
PushDown(x);
if (Son[x][1]) isRoot[Son[x][1]] = true;
Son[x][1] = y;
if (y) isRoot[y] = false;
Update(x);
y = x;
x = Father[x];
}
return y;
} void Make_Root(int x)
{
int t = Access(x);
Reverse(t);
} int Find_Root(int x)
{
int t = Access(x);
while (Son[t][0] != 0) t = Son[t][0];
return t;
} int main()
{
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; ++i)
{
Read(A[i]);
T[i] = A[i];
isRoot[i] = true;
Father[i] = 0;
}
int f, x, y, t, fx, fy;
for (int i = 1; i <= m; ++i)
{
Read(f); Read(x); Read(y);
switch (f)
{
case 0 :
Make_Root(x);
t = Access(y);
printf("%d\n", T[t]);
break; case 1 :
fx = Find_Root(x);
fy = Find_Root(y);
if (fx != fy)
{
Make_Root(x);
Splay(x);
Father[x] = y;
}
break; case 2 :
Make_Root(x);
Access(y);
Splay(y);
PushDown(y);
if (Son[y][0] == x)
{
isRoot[Son[y][0]] = true;
Father[Son[y][0]] = 0;
Son[y][0] = 0;
Update(y);
}
break; case 3 :
Splay(x);
A[x] = y;
Update(x);
break;
}
}
return 0;
}