php如何升级dirname(__FILE__)

I have a folder structure as follows:

我的文件夹结构如下:

mydomain.com
  ->Folder-A
  ->Folder-B

I have a string from Database that is '../Folder-B/image1.jpg', which points to an image in Folder-B.

我有一个来自数据库的字符串，它是'. /Folder-B/image1.jpg'，它指向的是Folder-B中的一个图像。

Inside a script in Folder-A, I am using dirname(FILE) to fetch the filename and I get mydomain.com/Folder-A. Inside this script, I need to get a string that says 'mydomain.com/Folder-B/image1.jpg. I tried

在Folder-A的脚本中，我使用dirname(文件)来获取文件名，我得到mydomain.com/Folder-A。在这个脚本中，我需要得到一个字符串，它的名称是“mydomain.com/folder - b/image1 .jpg”。我试着

$path=dirname(__FILE__).'/'.'../Folder-B/image1.jpg';

This shows up as mydomain.com%2FFolder-A%2F..%2FFolder-B%2Fimage1.jpg

这显示为mydomain.com%2FFolder-A%2F. %2FFolder-B%2Fimage1.jpg。

This is for a facebook share button, and this fails to fetch the correct image. Anyone know how to get the path correctly?

这是一个facebook的分享按钮，它不能获取正确的图片。有人知道如何正确地找到路径吗?

Edit: I hope to get a url >>>mydomain.com%2FFolder-B%2Fimage1.jpg

编辑:我希望得到一个url >>>mydomain.com%2FFolder-B%2Fimage1.jpg。

7 个解决方案

#1

122

For PHP < 5.3 use:

对于PHP < 5.3使用:

$upOne = realpath(dirname(__FILE__) . '/..');

Or in PHP 5.3+ use:

或在PHP 5.3+中使用:

$upOne = realpath(__DIR__ . '/..');

#2

Try this

试试这个

dirname(dirname( __ FILE__))

Edit: removed "./" because it isn't correct syntax. Without it, it works perfectly.

编辑:删除”。/因为它不是正确的语法。没有它，它就能完美地工作。

#3

If you happen to have php 7.0 you could use levels.

如果您碰巧有php 7.0，您可以使用级别。

dirname( __FILE__, 2 ) with the second parameter you can define the amount of levels you want to go back.

dirname(__FILE__， 2)和第二个参数，您可以定义要返回的级别的数量。

http://php.net/manual/en/function.dirname.php

#4

You could use PHP's dirname function. <?php echo dirname(__DIR__); ?>. That will give you the name of the parent directory of __DIR__, which stores the current directory.

可以使用PHP的dirname函数。< ?php echo目录名(__DIR__);? >。这将给出存储当前目录的__DIR__的父目录的名称。

#5

You can use realpath to remove unnessesary part:

您可以使用realpath删除unnessesary部分:

// One level up
echo str_replace(realpath(dirname(__FILE__) . '/..'), '', realpath(dirname(__FILE__)));

// Two levels etc.
echo str_replace(realpath(dirname(__FILE__) . '/../..'), '', realpath(dirname(__FILE__)));

On windows also replace \ with / if need that in URL.

在windows上也用/如果需要的话在URL中替换\。

#6

One level up, I have used:

有一个层次，我用过:

str_replace(basename(__DIR__) . '/' . basename(__FILE__), '', realpath(__FILE__)) . '/required.php';

or for php < 5.3:

或者php < 5.3:

str_replace(basename(dirname(__FILE__)) . '/' . basename(__FILE__), '', realpath(__FILE__)) . '/required.php';

#7

-3

I use this, if there is an absolute path (this is an example):

我用这个，如果有一个绝对路径(这是一个例子):

$img = imagecreatefromjpeg($_SERVER['DOCUMENT_ROOT']."/Folder-B/image1.jpg");

if there is a picture to show, this is enough:

如果有照片可以展示，这就足够了:

echo("<img src='/Folder-B/image1.jpg'>");

#1

122