I'm trying to select if a user rating (user.rating) is greater then 6 or if the user has more then 100 transactions (transaction table count). Basically count how many transactions the user has then where (transaction count >= 100 OR user rating >= 6).
我正在尝试选择一个用户等级(user.rating)是否大于6,或者如果用户有更多的100个事务(事务表计数)。基本上计算用户有多少事务(事务数>= 100或用户等级>= 6)。
SELECT *
FROM `user`
JOIN (SELECT COUNT(*)
FROM transaction
WHERE transaction.user_id=user.id
AND type='L'
AND status='S') AS tcount
WHERE (user.rating >= '6' OR tcount >= '100')
3 个解决方案
#1
2
Just another possible answer. I've created simplified schemas to test it, please try it and let me know the result.
另一个可能的答案。我已经创建了简化的模式来测试它,请尝试一下,并让我知道结果。
SELECT *
FROM user
WHERE user.rating >= 6 OR (SELECT COUNT(*) FROM transaction WHERE user_id = user.id and type = 'L' and status = 'S') >= 100;
#2
2
Use an alias on COUNT(*)
在COUNT(*)上使用别名
SELECT *
FROM `user`
JOIN (SELECT user_id, COUNT(*) cnt
FROM transaction
WHERE type='L'
AND status='S'
GROUP BY user_id) AS tcount
ON user.id = tcount.user_id
WHERE (user.rating >= '6' OR tcount.cnt >= '100')
#3
0
You can write that without the subquery, like this
没有子查询,可以这样写。
SELECT u.id
FROM `user` u
JOIN `transaction` t
ON t.user_id=u.id
WHERE t.type = 'L' AND t.status = 'S'
GROUP BY u.id
HAVING sum(case when u.rating >= 6 then 1 end) > 0 OR count(*) >= 100
#1
2
Just another possible answer. I've created simplified schemas to test it, please try it and let me know the result.
另一个可能的答案。我已经创建了简化的模式来测试它,请尝试一下,并让我知道结果。
SELECT *
FROM user
WHERE user.rating >= 6 OR (SELECT COUNT(*) FROM transaction WHERE user_id = user.id and type = 'L' and status = 'S') >= 100;
#2
2
Use an alias on COUNT(*)
在COUNT(*)上使用别名
SELECT *
FROM `user`
JOIN (SELECT user_id, COUNT(*) cnt
FROM transaction
WHERE type='L'
AND status='S'
GROUP BY user_id) AS tcount
ON user.id = tcount.user_id
WHERE (user.rating >= '6' OR tcount.cnt >= '100')
#3
0
You can write that without the subquery, like this
没有子查询,可以这样写。
SELECT u.id
FROM `user` u
JOIN `transaction` t
ON t.user_id=u.id
WHERE t.type = 'L' AND t.status = 'S'
GROUP BY u.id
HAVING sum(case when u.rating >= 6 then 1 end) > 0 OR count(*) >= 100