用java实现链表并解决约瑟夫环问题

时间:2021-11-09 13:32:19
package 栈和队列;
/**
 * 
 * 数到3的人出列 ,看最后能剩下谁
 * @author wangmeng
 *
 */
class Node {

	public  Object data;
	public  Node next;
	
	
	public Object getData() {
		return data;
	}
	public void setData(Object data) {
		this.data = data;
	}
	public Node getNext() {
		return next;
	}
	public void setNext(Node next) {
		this.next = next;
	}
	public Node() {
		super();
		// TODO Auto-generated constructor stub
	}
	public Node(Object data, Node next) {
		super();
		this.data = data;
		this.next = next;
	}

}



public class 用java实现链表并解决约瑟夫环问题 {
  public static void main(String[] args) {
	  Node node1 = new Node("1",null);
	   Node node2 = new Node("2",null);
	   Node node3 = new Node("3",null);
	   Node node4 = new Node("4",null);
	   Node node5 = new Node("5",null);
	   Node node6 = new Node("6",null);
	   Node node7 = new Node("7",null);
	   
	   
	   Node header = node1;
	   node1.next = node2;
	   node2.next = node3;
	   node3.next = node4;
	   node4.next = node5;
	   node5.next = node6;
	   node6.next = node7;
	   node7.next = node1;
	   
	   检测(header);
}

private static void 检测(Node header) {
		Node n = header;
		Node lastOne ;//表示上一个节点
		int  count  = 1 ;
		System.out.print("依次出列的顺序为:");
		while(n != n.next){//最后环中只剩下一个人,那肯定是它的下一个就是它本身  即  n=n.next
			
			lastOne = n;
			n = n.next;
			count ++ ;
			
			if(count == 3){//若数到3,出列
				lastOne.next = n.next;//上一个的节点的下一个就是当前的下一个   即lastOne.next = n.next;
				count = 0;//count清 0 
				System.out.print(n.data   + "   ");//打印出列的元素
			}
		}
		System.out.println();
		System.out.println("最后剩下的是:" + n.data);
}
    
   
   
   
}
运行结果:
依次出列的顺序为:3   6   2   7   5   1   
最后剩下的是:4