I am plotting number of correct and functioning sensors at each 100 runs.
我正在每100次运行中绘制正确且功能正常的传感器数量。
I will get the following plot:
我将得到以下情节：
The 100 readings taken for each of the runs is somewhat confusing. How can I make matlab plot
每次运行所获得的100个读数有些令人困惑。我怎样才能制作matlab图
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At every 5 values (5,15,20....)
每5个值（5,15,20 ....）
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The average of 5 runs so that number of plots will be 100/5.
平均5次运行，因此图的数量将是100/5。
can you help in these two cases thanks
你能帮助这两个案件谢谢吗？
if round=10 in the original case will have 10 bars,
如果在原始情况下圆= 10将有10个条，
With the formula given by @Richante data_to_plot = data(1:5:end); will have 2 bars. Great but when I plot will get values at Round 1 and 2. How to display that these are for rounds 1 and 5?
使用@Richante给出的公式data_to_plot = data（1：5：end）;将有2个酒吧。很棒但是当我的情节将在第1轮和第2轮获得值。如何显示这些是第1轮和第5轮？
1 个解决方案
#1
2
You can plot every 5th item by slicing the array:
您可以通过切割数组来绘制每第5个项目：
data = %1-by-100 array
data_to_plot = data(1:5:end);
To plot the average of 5 runs, you could do a for-loop:
要绘制5次运行的平均值，您可以执行for循环：
data_to_plot = zeros(1, 20);
for i=1:20
data_to_plot = mean(data((i-1)*5:i*5));
end
Or a neat way is to reshape the array into a 5-by-20 matrix and take the mean in the first dimension:
或者一个简洁的方法是将数组重新整形为5乘20的矩阵并取第一维中的均值：
data_to_plot = mean(reshape(data, 5, 20));
#1
2
You can plot every 5th item by slicing the array:
您可以通过切割数组来绘制每第5个项目：
data = %1-by-100 array
data_to_plot = data(1:5:end);
To plot the average of 5 runs, you could do a for-loop:
要绘制5次运行的平均值，您可以执行for循环：
data_to_plot = zeros(1, 20);
for i=1:20
data_to_plot = mean(data((i-1)*5:i*5));
end
Or a neat way is to reshape the array into a 5-by-20 matrix and take the mean in the first dimension:
或者一个简洁的方法是将数组重新整形为5乘20的矩阵并取第一维中的均值：
data_to_plot = mean(reshape(data, 5, 20));