Oracle - 将多个计数作为一个查询返回

I have a couple of queries, detailed below. I'd like to be able to run one SQL query which returns both counts, is this possible?

我有几个问题,详情如下。我希望能够运行一个返回两个计数的SQL查询,这可能吗?

select nvl(count(rowid), 0) from tablename where OPP = 'FOO' and date = 'BAZ';

select nvl(count(rowid), 0) from tablename where OPP = 'BAR' and date = 'BAZ';

I've only found MSSQL specific solutions in my searches so far.

到目前为止,我只在搜索中找到了MSSQL特定的解决方案。

3 个解决方案

#1

If you need them in a single row:

如果您需要它们在一行中:

SELECT
    COUNT(CASE OPP WHEN 'FOO' THEN 1 END),
    COUNT(CASE OPP WHEN 'BAR' THEN 1 END)
FROM tablename
WHERE OPP IN ('FOO', 'BAR') AND date = 'BAZ'

(The GROUP BY approach by Thilo is a better generic solution anyway.)

(无论如何,Thilo的GROUP BY方法是更好的通用解决方案。)

Edit: I've removed NVL(). I had forgotten why I never use it.

编辑:我删除了NVL()。我忘记了为什么我从不使用它。

#2

You could use a with statement:

你可以使用with语句:

with
count1 as (
select ...
),
count2 as (
select ...
)
select tot1, tot2
from count1, count2

#3

If the condition really looks like that (same table, only one field different in the groups):

如果条件真的如此(同一个表,组中只有一个字段不同):

select opp, count(*) from tablename
where date = 'BAZ'
group by opp
having opp in ('FOO', 'BAR');

For arbitrary queries:

对于任意查询:

select 'A', count(*) from tableA
union all
select 'B', count(*) from tableB

#1