In data structure Hash, hash function is used to convert a string(or any other type) into an integer smaller than hash size and bigger or equal to zero. The objective of designing a hash function is to "hash" the key as unreasonable as possible. A good hash function can avoid collision as less as possible. A widely used hash function algorithm is using a magic number 33, consider any string as a 33 based big integer like follow:
hashcode("abcd") = (ascii(a) * 333 + ascii(b) * 332 + ascii(c) *33 + ascii(d)) % HASH_SIZE
= (97* 333 + 98 * 332 + 99 * 33 +100) % HASH_SIZE
= 3595978 % HASH_SIZE
here HASH_SIZE is the capacity of the hash table (you can assume a hash table is like an array with index 0 ~ HASH_SIZE-1).
Given a string as a key and the size of hash table, return the hash value of this key.f
For key="abcd" and size=100, return 78
For this problem, you are not necessary to design your own hash algorithm or consider any collision issue, you just need to implement the algorithm as described.
Analysis:
We need to be careful about overflow, when we calculate the intermiedate result, we need be careful with overflow.
Solution 1:
Use long type.
class Solution {
/**
* @param key: A String you should hash
* @param HASH_SIZE: An integer
* @return an integer
*/
public int hashCode(char[] key,int HASH_SIZE) {
if (key.length==0) return 0;
int res = 0;
int base = 1;
for (int i=key.length-1;i>=0;i--){
res += modMultiply((int)key[i],base,HASH_SIZE);;
res %= HASH_SIZE;
base = modMultiply(base,33,HASH_SIZE);
}
return res;
} public int modMultiply(long a, long b, int HASH_SIZE){
long temp = a*b%HASH_SIZE;
return (int) temp;
} };
Solution 2:
Use int type to perform the multiply. However, change the way to calculate the whole expression. Using the way used in solution 1 will cause TLE.
class Solution {
/**
* @param key: A String you should hash
* @param HASH_SIZE: An integer
* @return an integer
*/
public int hashCode(char[] key,int HASH_SIZE) {
if (key.length==0) return 0;
int res = 0;
int base = 33;
for (int i=0;i<key.length;i++){
res = modMultiply(res,base,HASH_SIZE);
res += key[i];
res = res % HASH_SIZE;
}
return res;
} 19
public int modMultiply(int a, int b, int HASH_SIZE){
int res = a;
for (int j=1;j<b;j++){
int temp = (a-HASH_SIZE);
if (res+temp>=0) res = res+temp;
else res = res + a;
}
return res;
} };