如何删除介于两个其他列值之间的行? [重复]

时间:2023-01-31 09:18:41

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I have a data.frame1:

我有一个data.frame1:

BIN     CHR     BP1             BP2             Score   Value
12      chr1    29123222        29454711        -5.7648 599
116     chr13    45799118        45986770        -4.8403 473
117     chr5    46327104        46490961        -5.3036 536
121     chr6    50780759        51008404        -4.4165 415
133     chr18    63634657        63864734        -4.8096 469
147     chr1   77825305        78062178        -5.4671 559

I have a second data.frame2 like:

我有第二个data.frame2像:

    CHR     SNP             A1      A2      BP        INFO    OR      SE      P      NGT   
    chr1    rs10900604      A       G       29204555  0.774   1.01582 0.0143  0.2723  0
    chr3    rs12132517      A       G       79880711  0.604   0.98334 0.0253  0.5071  2
    chr14    rs11240777      A       G       79895429  0.818   0.98817 0.0139  0.3907  27
    chr18    rs147634896     T       C       63789900  0.623   1.02634 0.0259  0.3161  0
    chr6    rs143609865     A       T       77934001  0.617   1.01562 0.0317  0.6254  0

I am interested in keeping all the rows in data.frame2 that match the following crirteria: they much have the same CHR and a BP value between BP1 and BP2 of any of the rows in data.frame1.

我有兴趣保留data.frame2中与以下crirteria匹配的所有行:它们在data.frame1中的任何行的BP1和BP2之间具有相同的CHR和BP值。

For example, row one of data.frame2 has "chr1" and also has a "BP" between one of the BP ranges from data.frame1. Notice it doesn't fall into row 7's range, but it does fall into row 1's range. I would thus like to keep this row in data.frame2

例如,data.frame2的第一行具有“chr1”,并且在data.frame1之一的BP范围之间也具有“BP”。请注意,它不属于第7行的范围,但它确实属于第1行的范围。我想将此行保留在data.frame2中

Another example, row 4 of data.frame2 has "chr18" and BP 63789900 that falls within the BP range (between BP1 and BP2) of row 5 in data.frame1. I would thus like to keep this row in data.frame2

另一个例子,data.frame2的第4行具有“chr18”和BP 63789900,它们属于data.frame1中第5行的BP范围(BP1和BP2之间)。我想将此行保留在data.frame2中

Final example. Notice that row 5 in data.frame2 has a BP 77934001 that falls within BP1 and BP2 range for row 6 in data.frame1. Yet in data.frame2 "chr6" does not match with "chr1". I would like to delete this row.

最后的例子。请注意,data.frame2中的第5行具有BP 77934001,该数据位于data.frame1中第6行的BP1和BP2范围内。然而在data.frame2中,“chr6”与“chr1”不匹配。我想删除这一行。

I would also like to delete all the other rows that don't match both CHR and BP range at the same time.

我还想删除同时与CHR和BP范围不匹配的所有其他行。

I was thinking maybe if loop that had CHR1=CHR2, and BP>BP1 and BP

我想的可能是循环有CHR1 = CHR2,BP> BP1和BP

2 个解决方案

#1


4  

This ought to work using base R:

这应该使用基数R:

# merge the relevant data
dfmerge = merge(df1[c("CHR", "BP1", "BP2")], df2, by = "CHR")

# delete unwanted rows
dfmerge = dfmerge[(dfmerge$BP > dfmerge$BP1 & dfmerge$BP < dfmerge$BP2),]

# clean up columns
dfmerge[c("BP1", "BP2")] = list(NULL)

In generally, SQL can do this nice and concisely:

通常,SQL可以做到这一点,简洁明了:

library(sqldf)

sqldf("select df2.*
       from df2 inner join df1
       on df2.CHR = df1.CHR
       and df2.BP between df1.BP1 and df2.BP2")

#2


3  

Here is a dplyr approach:

这是一个dplyr方法:

d %>%
  left_join(d2) %>%
  filter(BP >= BP1 & BP <= BP2)

#1


4  

This ought to work using base R:

这应该使用基数R:

# merge the relevant data
dfmerge = merge(df1[c("CHR", "BP1", "BP2")], df2, by = "CHR")

# delete unwanted rows
dfmerge = dfmerge[(dfmerge$BP > dfmerge$BP1 & dfmerge$BP < dfmerge$BP2),]

# clean up columns
dfmerge[c("BP1", "BP2")] = list(NULL)

In generally, SQL can do this nice and concisely:

通常,SQL可以做到这一点,简洁明了:

library(sqldf)

sqldf("select df2.*
       from df2 inner join df1
       on df2.CHR = df1.CHR
       and df2.BP between df1.BP1 and df2.BP2")

#2


3  

Here is a dplyr approach:

这是一个dplyr方法:

d %>%
  left_join(d2) %>%
  filter(BP >= BP1 & BP <= BP2)