My program asks the individual to input 2 numbers (ie; 10 and 20). I would like the output to be:
我的程序要求个人输入2个数字(即10和20)。我希望输出为:
Even numbers: 10 12 14 16 18 20
偶数:10 12 14 16 18 20
My code:
System.out.println("Enter an integer:");
int firstNum = keyboard.nextInt();
System.out.println("Enter another integer larger than the first one:");
int secondNum = keyboard.nextInt();
System.out.println();
int mod = firstNum % 2;
while ((firstNum < secondNum) && mod == 0)
{
firstNum = firstNum + 2;
System.out.print("Even numbers" +firstNum);
}
1 个解决方案
#1
1
You are close to the result you are after, just need to rearrange the order of a couple of lines and add one if
check.
你接近你想要的结果,只需要重新排列几行的顺序,如果检查就添加一行。
I have made a complete example that runs as expected and allows for both odd and even numbers. You can replace your code with the following:
我做了一个完整的例子,按预期运行,允许奇数和偶数。您可以使用以下代码替换您的代码:
public static void main(String[] args)
{
Scanner keyboard = new Scanner(System.in);
System.out.println("Enter an integer:");
int firstNum = keyboard.nextInt();
System.out.println("Enter another integer larger than the first one:");
int secondNum = keyboard.nextInt();
System.out.println();
int mod = firstNum % 2;
//If first number is odd, increase by one to make it even.
if (mod != 0)
{
firstNum++;
}
System.out.print("Even Numbers: ");
while (firstNum <= secondNum)
{
System.out.print(firstNum + " ");
firstNum = firstNum + 2;
}
keyboard.close();
}
#1
1
You are close to the result you are after, just need to rearrange the order of a couple of lines and add one if
check.
你接近你想要的结果,只需要重新排列几行的顺序,如果检查就添加一行。
I have made a complete example that runs as expected and allows for both odd and even numbers. You can replace your code with the following:
我做了一个完整的例子,按预期运行,允许奇数和偶数。您可以使用以下代码替换您的代码:
public static void main(String[] args)
{
Scanner keyboard = new Scanner(System.in);
System.out.println("Enter an integer:");
int firstNum = keyboard.nextInt();
System.out.println("Enter another integer larger than the first one:");
int secondNum = keyboard.nextInt();
System.out.println();
int mod = firstNum % 2;
//If first number is odd, increase by one to make it even.
if (mod != 0)
{
firstNum++;
}
System.out.print("Even Numbers: ");
while (firstNum <= secondNum)
{
System.out.print(firstNum + " ");
firstNum = firstNum + 2;
}
keyboard.close();
}