I have a table OrderDetails with the following schema:
我有一个表OrderDetails与以下架构:
----------------------------------------------------------------
| OrderId | CopyCost | FullPrice | Price | PriceType |
----------------------------------------------------------------
| 16 | 50 | 100 | 50 | CopyCost |
----------------------------------------------------------------
| 16 | 50 | 100 | 100 | FullPrice |
----------------------------------------------------------------
| 16 | 50 | 100 | 50 | CopyCost |
----------------------------------------------------------------
| 16 | 50 | 100 | 50 | CopyCost |
----------------------------------------------------------------
I need a query that will surmise the above table into a new table with the following schema:
我需要一个查询,将上面的表推测为具有以下模式的新表:
----------------------------------------------------------------
| OrderId | ItemCount | TotalCopyCost | TotalFullPrice |
----------------------------------------------------------------
| 16 | 4 | 150 | 100 |
----------------------------------------------------------------
Currently I am using a Group By on the Order.Id to the the item count. But I do not know how to conditionally surmise the CopyCost and FullPrice values.
目前我在Order.Id上使用Group By来计算项目数。但我不知道如何有条理地推测CopyCost和FullPrice值。
Any help would be much appreciated.
任何帮助将非常感激。
Regards Freddie
关心弗雷迪
4 个解决方案
#1
54
Try
尝试
SELECT OrderId,
COUNT(*) ItemCount,
SUM(CASE WHEN PriceType = 'CopyCost' THEN Price ELSE 0 END) TotalCopyCost,
SUM(CASE WHEN PriceType = 'FullPrice' THEN Price ELSE 0 END) TotalFullPrice
FROM OrderDetails
GROUP BY OrderId
SQLFiddle
#2
4
Try this query
试试这个查询
select
orderId,
count(*) as cnt,
sum(if(pricetype='CopyCost', CopyCost, 0)) as totalCopyCost,
sum(if(pricetype='FullPrice', FullPrice, 0)) as totalFullPrice
from
tbl
group by
orderId
SQL FIDDLE:
| ORDERID | CNT | TOTALCOPYCOST | TOTALFULLPRICE |
--------------------------------------------------
| 16 | 4 | 150 | 100 |
#3
3
Could you use:
你能用:
SELECT
OrderId,
Count(1) as ItemCount,
SUM(CASE WHEN PriceType = 'CopyCost'
THEN CopyCost ELSE 0 END) AS TotalCopyCost,
SUM(CASE WHEN PriceType = 'FullPrice'
THEN FullPrice ELSE 0 END) AS TotalFullPrice
FROM OrderDetails
GROUP BY OrderId
#4
0
You could also try...
你也可以试试......
select A.OrderID, A.ItemCount,B.TotalCopyCost, C.TotalFullPrice
from (select OrderID, count(*) as ItemCount from orderdetails) as A,
(select OrderID, sum(CopyCost) as TotalCopyCost from orderdetails where PriceType = 'CopyCost') as B,
(select OrderID, sum(FullPrice) as TotalFullPrice from orderdetails where PriceType = 'FullPrice') as C
where A.OrderID = B.OrderID
SQLFiddle: http://sqlfiddle.com/#!2/946af/6
SQLFiddle:http://sqlfiddle.com/#!2/946af/6
#1
54
Try
尝试
SELECT OrderId,
COUNT(*) ItemCount,
SUM(CASE WHEN PriceType = 'CopyCost' THEN Price ELSE 0 END) TotalCopyCost,
SUM(CASE WHEN PriceType = 'FullPrice' THEN Price ELSE 0 END) TotalFullPrice
FROM OrderDetails
GROUP BY OrderId
SQLFiddle
#2
4
Try this query
试试这个查询
select
orderId,
count(*) as cnt,
sum(if(pricetype='CopyCost', CopyCost, 0)) as totalCopyCost,
sum(if(pricetype='FullPrice', FullPrice, 0)) as totalFullPrice
from
tbl
group by
orderId
SQL FIDDLE:
| ORDERID | CNT | TOTALCOPYCOST | TOTALFULLPRICE |
--------------------------------------------------
| 16 | 4 | 150 | 100 |
#3
3
Could you use:
你能用:
SELECT
OrderId,
Count(1) as ItemCount,
SUM(CASE WHEN PriceType = 'CopyCost'
THEN CopyCost ELSE 0 END) AS TotalCopyCost,
SUM(CASE WHEN PriceType = 'FullPrice'
THEN FullPrice ELSE 0 END) AS TotalFullPrice
FROM OrderDetails
GROUP BY OrderId
#4
0
You could also try...
你也可以试试......
select A.OrderID, A.ItemCount,B.TotalCopyCost, C.TotalFullPrice
from (select OrderID, count(*) as ItemCount from orderdetails) as A,
(select OrderID, sum(CopyCost) as TotalCopyCost from orderdetails where PriceType = 'CopyCost') as B,
(select OrderID, sum(FullPrice) as TotalFullPrice from orderdetails where PriceType = 'FullPrice') as C
where A.OrderID = B.OrderID
SQLFiddle: http://sqlfiddle.com/#!2/946af/6
SQLFiddle:http://sqlfiddle.com/#!2/946af/6