I did multiple searches for an answer to this (on SO and elsewhere), but haven't found an answer that really fit my needs (if it's out there, I apologize in advance).
我对这个问题进行了多次搜索(等等),但没有找到一个真正符合我需要的答案(如果它确实存在,我提前道歉)。
I have a query, using PHP, that returns an array from a database (WordPress). Basically what I want to do is look at a column's value, and then LIMIT based on that value. Here's the array that's returned for a better idea:
我有一个使用PHP的查询,它从数据库(WordPress)返回一个数组。基本上我要做的是看一列的值,然后根据这个值限制。这是为了更好的想法而返回的数组:
http://pastebin.com/AC043qfh
In the query, you'll notice that the value for post_parent repeats for several of returned arrays. What I want to do is have it LIMIT to 3 based on the post_parent value e.g. I want 3 entries for post_parent 79, 87, 100, etc.
在查询中,您将注意到post_parent的值对几个返回数组重复。我要做的是根据post_parent值将其限制为3,例如,我希望post_parent 79、87、100等有3个条目。
I'm not well versed (see: at all) in MySQL queries, but this is what I have to get that array:
我对MySQL查询不是很精通(看:一点也不),但这就是我要得到这个数组的原因:
SELECT DISTINCT ID, guid, post_parent, post_title
FROM $wpdb->posts p
WHERE p.post_type = 'attachment'
AND p.post_mime_type LIKE 'image/%'
AND p.post_status = 'inherit'
AND p.post_parent IN
(SELECT object_id FROM $term_relationships WHERE term_taxonomy_id = $post_term)
I've tried using GROUP BY, but that didn't get me what I wanted. Any help is appreciated.
我试过用GROUP BY,但是没有得到我想要的。任何帮助都是感激。
EDIT Just to clarify, these are the results I want: http://pastebin.com/pWXdUuXv
编辑只是为了澄清,这些是我想要的结果:http://pastebin.com/pWXdUuXv
1 个解决方案
#1
3
This might do the trick: (I'm assuming ID is unique, if not substitute something that is)
这可能会起到这样的作用:(我假设ID是惟一的,如果不能替换它的话)
SELECT
p.ID, guid, post_parent, post_title
FROM (
SELECT
a.ID as ID,
COUNT(*) as rank
FROM (
SELECT ID, post_parent
FROM $wpdb->posts
WHERE post_type = 'attachment'
AND post_mime_type LIKE 'image/%'
AND post_status = 'inherit'
) AS a
JOIN (
SELECT ID, post_parent
FROM $wpdb->posts
WHERE post_type = 'attachment'
AND post_mime_type LIKE 'image/%'
AND post_status = 'inherit'
) AS b ON b.ID <= a.ID AND b.post_parent = a.post_parent
GROUP BY a.ID
) AS r
JOIN $wpdb->posts p ON r.ID = p.ID AND r.rank <= 3
WHERE p.post_parent IN (
SELECT object_id FROM $term_relationships
WHERE term_taxonomy_id = $post_term)
GROUP BY p.ID
;
EDIT: Attempt to include category in rank so it'll actually work.
编辑:尝试在等级中包含类别,这样它就可以工作了。
Specifying conditions twice is a bit ugly, but I didn't see an easy way around it.
两次指定条件有点难看,但是我没有找到一个简单的方法。
#1
3
This might do the trick: (I'm assuming ID is unique, if not substitute something that is)
这可能会起到这样的作用:(我假设ID是惟一的,如果不能替换它的话)
SELECT
p.ID, guid, post_parent, post_title
FROM (
SELECT
a.ID as ID,
COUNT(*) as rank
FROM (
SELECT ID, post_parent
FROM $wpdb->posts
WHERE post_type = 'attachment'
AND post_mime_type LIKE 'image/%'
AND post_status = 'inherit'
) AS a
JOIN (
SELECT ID, post_parent
FROM $wpdb->posts
WHERE post_type = 'attachment'
AND post_mime_type LIKE 'image/%'
AND post_status = 'inherit'
) AS b ON b.ID <= a.ID AND b.post_parent = a.post_parent
GROUP BY a.ID
) AS r
JOIN $wpdb->posts p ON r.ID = p.ID AND r.rank <= 3
WHERE p.post_parent IN (
SELECT object_id FROM $term_relationships
WHERE term_taxonomy_id = $post_term)
GROUP BY p.ID
;
EDIT: Attempt to include category in rank so it'll actually work.
编辑:尝试在等级中包含类别,这样它就可以工作了。
Specifying conditions twice is a bit ugly, but I didn't see an easy way around it.
两次指定条件有点难看,但是我没有找到一个简单的方法。