NSString *string = [myString stringByReplacingOccurrencesOfString:@"<wow>" withString:someString];
I have this code. Now suppose my app's user enters two different strings I want to replace with two different other strings, how do I achieve that? I don't care if it uses private APIs, i'm developing for the jailbroken platform. My user is going to either enter or or . I want to replace any occurrences of those strings with their respective to-be-replaced-with strings :)
我有这段代码。假设我的app用户输入两个不同的字符串我想用两个不同的字符串替换,我如何实现呢?我不关心它是否使用私有api,我正在开发一个越狱平台。我的用户要么输入要么。我想用它们各自的要替换的字符串替换这些字符串的出现:)
Thanks in advance :P
提前谢谢:P
4 个解决方案
#1
6
Both dasblinkenlight’s and Matthias’s answers will work, but they both result in the creation of a couple of intermediate NSStrings; that’s not really a problem if you’re not doing this operation often, but a better approach would look like this.
dasblinkenlight和Matthias的答案都是可行的,但它们都导致了两个中间的nsstring;如果你不经常做这个操作,这并不是真正的问题,但是更好的方法应该是这样的。
NSMutableString *myStringMut = [[myString mutableCopy] autorelease];
[myStringMut replaceOccurrencesOfString:@"a" withString:somethingElse];
[myStringMut replaceOccurrencesOfString:@"b" withString:somethingElseElse];
// etc.
You can then use myStringMut
as you would’ve used myString
, since NSMutableString is an NSString subclass.
然后可以像使用myString那样使用myStringMut,因为NSMutableString是一个NSString子类。
#2
6
The simplest solution is running stringByReplacingOccurrencesOfString
twice:
最简单的解决方案是运行stringByReplacingOccurrencesOfString两次:
NSString *string = [[myString
stringByReplacingOccurrencesOfString:@"<wow>" withString:someString1]
stringByReplacingOccurrencesOfString:@"<boo>" withString:someString2];
#3
2
I would just run the string replacing method again
我将再次运行字符串替换方法
NSString *string = [myString stringByReplacingOccurrencesOfString:@"foo" withString:@"String 1"];
string = [string stringByReplacingOccurrencesOfString:@"bar" withString:@"String 2"];
#4
2
This works well for me in Swift 3.1
在Swift 3.1中,这对我来说很适用
let str = "hi hello hey"
var replacedStr = (str as NSString).replacingOccurrences(of: "hi", with: "Hi")
replacedStr = (replacedStr as NSString).replacingOccurrences(of: "hello", with: "Hello")
replacedStr = (replacedStr as NSString).replacingOccurrences(of: "hey", with: "Hey")
print(replacedStr) // Hi Hello Hey
#1
6
Both dasblinkenlight’s and Matthias’s answers will work, but they both result in the creation of a couple of intermediate NSStrings; that’s not really a problem if you’re not doing this operation often, but a better approach would look like this.
dasblinkenlight和Matthias的答案都是可行的,但它们都导致了两个中间的nsstring;如果你不经常做这个操作,这并不是真正的问题,但是更好的方法应该是这样的。
NSMutableString *myStringMut = [[myString mutableCopy] autorelease];
[myStringMut replaceOccurrencesOfString:@"a" withString:somethingElse];
[myStringMut replaceOccurrencesOfString:@"b" withString:somethingElseElse];
// etc.
You can then use myStringMut
as you would’ve used myString
, since NSMutableString is an NSString subclass.
然后可以像使用myString那样使用myStringMut,因为NSMutableString是一个NSString子类。
#2
6
The simplest solution is running stringByReplacingOccurrencesOfString
twice:
最简单的解决方案是运行stringByReplacingOccurrencesOfString两次:
NSString *string = [[myString
stringByReplacingOccurrencesOfString:@"<wow>" withString:someString1]
stringByReplacingOccurrencesOfString:@"<boo>" withString:someString2];
#3
2
I would just run the string replacing method again
我将再次运行字符串替换方法
NSString *string = [myString stringByReplacingOccurrencesOfString:@"foo" withString:@"String 1"];
string = [string stringByReplacingOccurrencesOfString:@"bar" withString:@"String 2"];
#4
2
This works well for me in Swift 3.1
在Swift 3.1中,这对我来说很适用
let str = "hi hello hey"
var replacedStr = (str as NSString).replacingOccurrences(of: "hi", with: "Hi")
replacedStr = (replacedStr as NSString).replacingOccurrences(of: "hello", with: "Hello")
replacedStr = (replacedStr as NSString).replacingOccurrences(of: "hey", with: "Hey")
print(replacedStr) // Hi Hello Hey