Sorting In Linear Time
之前尝试过很多的排序算法, 都是基于比较的排序算法(base on comparing)
Collection of algorithm for sorting (part one)
http://blog.csdn.net/cinmyheart/article/details/39268783
Collection of algorithm for sorting (part two)
http://blog.csdn.net/cinmyheart/article/details/39396651
Collection of algorithm for sorting (part three)
http://blog.csdn.net/cinmyheart/article/details/39413037
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前面一些基于比较的排序算法的时间复杂度:
时间复杂度为O(n)的Counting Sort 计数排序
所有的排序算法都会在这个O(n)面前黯然失色 ...
这里给出两个语言实现的版本
C语言实现:
/********************************************************* Code writer : EOF Code date : 2014.01.11 Code file : counting_sort.c e-mail : jasonleaster@gmail.com Code description: Here is a implementation for counting sort. If you find something wrong with my code, please touch me by e-mail. *********************************************************/ #include <stdio.h> #include <stdlib.h> int counting_sort(int *num,int array_size) { if(!num) { return -1; } int *p_tmp = (int*)malloc(sizeof(int)*array_size); if(!p_tmp) { printf("malloc failed %d\n",__LINE__); return 0; } int i = 0; int max_value = 0; for(i = 0; i < array_size; i++) { max_value = max_value > num[i] ? max_value : num[i]; p_tmp[i] = num[i]; } int counter_size = max_value + 1; int *p_counter = (int*)malloc(sizeof(int)*counter_size); if(!p_counter) { printf("malloc failed %d\n",__LINE__); return 0; } //initialization for(i = 0; i < counter_size; i++) { p_counter[i] = 0; } //counting for(i = 0; i < array_size; i++) { p_counter[num[i]] += 1; } //caculating for(i = 1; i < counter_size; i++) { p_counter[i] += p_counter[i-1]; } //output from bigger element to smaller element for(i = array_size -1;i >= 0; i--) { num[p_counter[p_tmp[i]] - 1] = p_tmp[i]; p_counter[p_tmp[i]] -= 1; } free(p_counter); free(p_tmp); return 0; } int main() { int array[] = {1,3,4,3,2,7,4,0}; int size_array = sizeof(array)/sizeof(array[0]); int i = 0; printf("Before sorting:array[] = \n"); for(i = 0; i < size_array; i++) { printf("\t%d",array[i]); } printf("\n"); counting_sort(array,size_array); printf("After sorting:array[] = \n"); for(i = 0; i < size_array; i++) { printf("\t%d",array[i]); } printf("\n"); return 0; }
Python实现:
""" Code writer : EOF Code date : 2014.01.11 Code file : counting_sort.py e-mail : jasonleaster@gmail.com Code description: Here is a implementation for counting sort. If you find something wrong with my code, please touch me by e-mail. """ def counting_sort(array) : array_size = len(array) max_value = 0 for i in range(0,array_size) : if max_value < array[i] : max_value = array[i] buf_size = max_value + 1 buf = [0] * buf_size ret = [0] * array_size for i in range(0, array_size) : buf[array[i]] += 1 for i in range(1, buf_size) : buf[i] += buf[i-1] for i in range(array_size - 1, -1, -1) : ret[buf[array[i]] - 1] = array[i] buf[array[i]] -= 1 return ret array = [1,3,4,3,2,7,4,0] print "Befor sorting" ,array sorted_ary = counting_sort(array) print "After sorting", sorted_ary
update : 2015.01.12
之前的代码有误,现已更正
计数排序的精髓就在于index索引.
ret[buf[array[i]] - 1] = array[i]
既不是向东,也不是向西,而是指向内心