Groovy：我如何按字符串长度顺序对String：的ArrayList进行排序？

How do I sort an ArrayList of String's in length-of-string order in Groovy?

如何在Groovy中按字符串长度顺序对String的ArrayList进行排序？

Code:

码：

def words = ['groovy', 'is', 'cool']
// your code goes here:
// code that sorts words in ascending length-of-word order
assert words == ['is', 'cool', 'groovy']

There are certainly more than one way to do it - so I'll grant the answer to the person who provides the most elegant solution.

肯定有不止一种方法可以做到 - 所以我会给那些提供最优雅解决方案的人一个答案。

1 个解决方案

#1

words = words.sort { it.size() }

To get descending order

要降序

words = words.sort { -it.size() }