如何(安全地)划分最大值,从而产生浮点值?

时间:2022-02-04 07:14:42

I want to calculate conversion factors. For this I have to divide the maximum value of e.g. ushort by the maximum value of uchar.

我想计算转换因子。为此我必须将最大值除以例如按uchar的最大值ushort。

I want to do this dynamically, by passing a parameter into a function or a typename. Then I want to select the max values and perform the calculation.

我想通过将参数传递给函数或类型名来动态地执行此操作。然后我想选择最大值并执行计算。

There are two problems:

有两个问题:

  1. How do I dynamically select the max value?
  2. 如何动态选择最大值?
  3. How can I safely divide the two values?
  4. 我怎样才能安全地划分这两个值?

All values are known to fit into the range of double.

已知所有值都适合双倍范围。

Ideally I would want to do something like:

理想情况下,我想做的事情如下:

double x = numeric_limits<T>::max / numeric_limits<T2>::max;

However that is not correct/possible.

然而,这是不正确/可能的。

1 个解决方案

#1


3  

Your proposed idea should work:

您提出的想法应该有效:

#include <iostream>
#include <limits>

template <typename T, typename T2>
double get_ratio()
{
    return static_cast<double>(std::numeric_limits<T>::max()) / std::numeric_limits<T2>::max();
}

int main()
{
    auto ratio = get_ratio<unsigned short, unsigned char>();
    std::cout << ratio << '\n';
    return 0;
}

demo

演示

#1


3  

Your proposed idea should work:

您提出的想法应该有效:

#include <iostream>
#include <limits>

template <typename T, typename T2>
double get_ratio()
{
    return static_cast<double>(std::numeric_limits<T>::max()) / std::numeric_limits<T2>::max();
}

int main()
{
    auto ratio = get_ratio<unsigned short, unsigned char>();
    std::cout << ratio << '\n';
    return 0;
}

demo

演示