PHP：使用变量名回显常量

How can I do that?

我怎样才能做到这一点?

I have something like:

我有类似的东西:

define($stuff.'_FOO', 'whatever');
echo $stuff.'_FOO';

and it doesn't work :(

它不起作用:(

I just want to echo the constant's value...

我只想回应常数的价值......

2 个解决方案

#1

Check out constant().

检查常量()。

In your case:

在你的情况下:

echo constant($stuff . '_FOO');

#2

First make a constant:

先做一个常数:

define("FOO_BAR", "something more");

then you can get the value by using constant():

然后你可以使用constant()来获取值:

echo constant("FOO_BAR");

Read more about constants in the manual.

阅读手册中有关常量的更多信息。