如何使用scanf读取由空格分隔的数字

I want to read numbers(integer type) separated by spaces using scanf() function.
I have read the following

我想要读取使用scanf()函数分隔的数字(integer类型)。我读过以下内容

C, reading multiple numbers from single input line (scanf?)
how to read scanf with spaces
It doesn't help me much. How can I read numbers with space as delimiter. For e.g. I have following numbers as input 2 5 7 4 3 8 18 now I want to store these in different variables.
Please help.

从单输入行读取多个数字(scanf?)如何用空格来读取scanf对我的帮助不大。如何以空格作为分隔符来读取数字。例如，我有以下数字作为输入2 5 7 4 3 8 18现在我想把它们存储在不同的变量中。请帮助。

8 个解决方案

#1

I think by default values read by scanf with space/enter. Well you can provide space between '%d' if you are printing integers. Also same for other cases.

我认为scanf使用空格/enter的默认值。如果要打印整数，可以在'%d'之间提供空格。其他情况也是如此。

scanf("%d %d %d", &var1, &var2, &var3);

Similarly if you want to read comma separated values use :

类似地，如果你想读逗号分隔的值，请使用:

scanf("%d,%d,%d", &var1, &var2, &var3);

#2

It should be as simple as using a list of receiving variables:

它应该像使用接收变量列表一样简单:

scanf("%i %i %i", &var1, &var2, &var3);

scanf(“%i %i %i”，&var1， &var2， &var3);

#3

Read as %s[^\n]

解读为% s[^ \ n]

and then read each char of the string , and do a atoi() if it is a char , else ignore it.

然后读取字符串的每个字符，如果它是一个字符，则执行atoi()，否则忽略它。

#4

int main()
{
char string[200];
int g,a,i,G[20],A[20],met;

gets(string);
g=convert_input(G,string);

for(i=0;i<=g;i++)
    printf("\n%d>>%d",i,G[i]);
return 0;
}

int convert_input(int K[],char string[200])
{
int j=0,i=0,temp=0;
while(string[i]!='\0')
{
    temp=0;
    while(string[i]!=' ' && string[i]!='\0')
        temp=temp*10 + (string[i++]-'0') ;
    if(string[i]==' ')
        i++;
    K[j++]=temp;
}
return j-1;
}

#5

scanf uses any whitespace as a delimiter, so if you just say scanf("%d", &var) it will skip any whitespace and then read an integer (digits up to the next non-digit) and nothing more.

scanf使用任何空格作为分隔符，所以如果你只说scanf(“%d”，&var)，它将跳过任何空格，然后读取一个整数(到下一个非数字的数字)，再没有别的了。

Note that whitespace is any whitespace -- spaces, tabs, newlines, or carriage returns. Any of those are whitespace and any one or more of them will serve to delimit successive integers.

注意，空格是任何空格——空格、制表符、换行符或回车符。其中任何一个都是空格，任何一个或多个空格都可以用来分隔连续的整数。

#6

C++ code in TurboC++ compiler:

c++ TurboC中的代码+编译器:

#include<iostream.h>
#include<stdlib.h>
#include<string.h>
#include<conio.h>
void main()
{
    int l=0,i=0;
    char *a,*t;
    clrscr();
    int n;
    cout<<"\nEnter a string: ";
    cin>>t;
    a=strdup(t); //duplicate
    while(strlen(a)){
        a = strtok(a, ","); //gives string upto where ',' is found
        n=atoi(a);
        l+=strlen(a); //we save the length
        cout<<"n= "<<n<<" a= "<<a<<" "<<strlen(a)<<endl; //simple output
        a=strdup(t+l+i); //updating the same pointer with rest part
        i++; //counting number of ','s
    }
    getch();
}  

#7

int main(){
    int A[1000];
    char *tok = NULL;
    char *savePtr = NULL;
    char str[1000] = "";
    int totalElement=0;
    printf("Enter space seperated string\n");
    scanf("%[^\n]s", str);
    savePtr = str;

    while((tok=strtok_r(savePtr, " ", &savePtr))){
        A[totalElement++] = atoi(tok);
    }

    for(int i = 0; i < totalElement; i++)
        printf("%d ", A[i]);
}

#8

Here i just wrote a simple c code for adding two numbers and taking input from user. now a and b are inputs and %d % or %d%d doesn't matter, what you've to do that as soon as input asked just write first input then press spacebar then write 2nd input and so on.thing is even if u just put space between %d's then also no change will be change. hence, i think that best way is this nly.

这里我只写了一个简单的c代码，用于添加两个数字并从用户那里获取输入。现在a和b是输入，%d%或%d%d都不重要，只要输入被要求，你要做的就是写第一个输入然后按空格键然后写第二个输入，等等。即使你只是在%d之间放个空格，也没有变化。因此，我认为最好的办法就是这样。