jQuery：将具有不一致行数据的XML解析为表

This is probably a very rookie question but i am stumped.

这可能是一个非常新秀的问题,但我很难过。

I have the following code which is parsing an XML file and putting each element into a table. My problem is that there is not always nine elements in each row and the names of each element changes between XML files. Is there any way to create a loop that runs through each row (without knowing the element name (col0, col1, etc) ) and puts it into a table?

我有以下代码,它解析XML文件并将每个元素放入表中。我的问题是每行中并不总是有九个元素,每个元素的名称在XML文件之间都会发生变化。有没有办法创建一个遍历每一行的循环(不知道元素名称(col0,col1等))并将其放入表中?

The XML goes like this:

XML是这样的:

<row>
    <Col0>titles</Col0>
    <Col1>more titles</Col1>
    <Col2>title</Col2>
    <Col3>name</Col3>
    <Col4>another name</Col4>
    <Col5>different name</Col5>
    <Col6></Col6>
    <Col7></Col7>
    <Col8></Col8>
</row>
<row>
    <Col0>5:58</Col0>
    <Col1>-</Col1>
    <Col2>6:08</Col2>
    <Col3>6:11</Col3>
    <Col4>6:15</Col4>
    <Col5>6:19</Col5>
    <Col6></Col6>
    <Col7></Col7>
    <Col8></Col8>
</row>

etc....

Here is my code:

这是我的代码:

<script type="text/javascript">
    $(document).ready(function()
  {
    $.get('newlayout.xml', function(d){
    $('.tabl').append('<table>');

    $(d).find('row').each(function(){

        var $row = $(this);

        var col01 = $row.find('Col0').text();
        var col02 = $row.find('Col1').text();
        var col03 = $row.find('Col2').text();
        var col04 = $row.find('Col3').text();
        var col05 = $row.find('Col4').text();
        var col06 = $row.find('Col5').text();
        var col07 = $row.find('Col6').text();
        var col08 = $row.find('Col7').text();
        var col09 = $row.find('Col8').text();


        html = '<tr>'  
        html += '<td style="width:80px"> ' + col01 + '</td>';
        html += '<td style="width:80px"> ' + col02 + '</td>' ;
        html += '<td style="width:80px"> ' + col03 + '</td>' ;
        html += '<td style="width:80px"> ' + col04 + '</td>' ;
        html += '<td style="width:80px"> ' + col05 + '</td>' ;
        html += '<td style="width:80px"> ' + col06 + '</td>' ;
        html += '<td style="width:80px"> ' + col07 + '</td>' ;
        html += '<td style="width:80px"> ' + col08 + '</td>' ;
        html += '<td style="width:80px"> ' + col09 + '</td>' ;
                    html += '</tr>';

        $('.tabl').append($(html));

    });
});
});

Thanks in advance,
Tom

先谢谢你,汤姆

3 个解决方案

#1

try the following:

尝试以下方法:

$('row').each(function(){
    var $row = $(this);
    $('.tabl').append($('<tr></tr>').append($row.children().wrapInner('<td style="width:80px"></td>').find('td')));
})

Working example at jsFiddle.

jsFiddle的工作示例。

I think you can follow what's happening here. If not, ask away. It's mostly an issue of understanding the different jQuery functions, and for this nothing beats api.jquery.com

我想你可以关注这里发生的事情。如果没有,请求离开。这主要是理解不同jQuery函数的问题,为此没有什么比api.jquery.com更好的了

edit: This version gets rid of the empty cells, by selecting only those cells that are a parent of something (i.e. not empty):

编辑:此版本通过仅选择那些作为父项(即非空)的单元格来消除空单元格:

$('row').each(function(){
    var $row = $(this);
    $('.tabl').append($('<tr></tr>').append($row.children().wrapInner('<td style="width:80px"></td>').find('td:parent')));
})

#2

$(d).find('row').each(function() {
    var $row = $(this);
    html = '<tr>';
    var i = 0;

    while (true) {
        if ($.trim((colX = $row.find('Col' + i).text())) !== '') {
            html += '<td style="width:80px"> ' + colX + '</td>';
            i++;
        }
        else {
            break;
        }
    }

    html += '</tr>';
    $('.tabl').append($(html));
});

#3

If you want to only have columns for fields with a name in the first row, then this will work for you:

如果您只想为第一行中具有名称的字段添加列,那么这将适用于您:

http://jsfiddle.net/entropo/ffyDT/

$('row').each(function() {
    var $row = $(this),
        fieldcount = fieldcount || 0,
        afterfirst;
    if (! afterfirst) {
        fieldcount = $row.find(':not(:empty)').length;
        afterfirst = 1;
    }

    $('.tabl').append($('<tr />').append($row.children(':lt('+fieldcount+')')
        .wrapInner('<td />').find('td')));
});

#1