1 1 1 ab
2 2 1 cd
3 1 2 we
4 1 1 aa
5 1 2 bb
6 1 1 cc
……
想将 外键b和c相同的合并在一起显示字段d
得到
1 1 ab+aa+cc
1 2 we+bb
2 2 cd
……
求sql不要太复杂了
9 个解决方案
#1
合并列值
#2
http://www.cnblogs.com/codeyu/archive/2010/05/25/1743474.html
利用 sql 的 xml 来实现合并. 具体 SQL 不帮你写了,参考上面的 一起学习下
#3
合并列值
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)
1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb
/*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(2 行受影响)
*/
--SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id
/*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc
(2 row(s) affected)
*/
drop table tb
#4
select min(a) a,b, d=stuff((select '+'+d from tb t where b=tb.b and c=tb.c for xml path('')), 1, 1, '')
from tb
group by b ,c
/*
a,b,d
1,1,ab+aa+cc
3,1,we+bb
2,2,cd
(3 行受影响)
#5
select min(a) a,b, d=stuff((select '+'+d from tb t where b=tb.b and c=tb.c for xml path('')), 1, 1, '')
from tb
group by b ,c
order by b
#6
+1
#7
--sql 2000
create function dbo.f_str(@b int,@c int) returns varchar(1000)
as
begin
declare @str varchar(1000)
select @str = isnull(@str + '+' , '') + cast(d as varchar) from tb where b = @b and c = @c
return @str
end
go
--调用函数
select b,c , d = dbo.f_str(b,c) from tb group by b, c
#8
--sql 2005
select b , c , d = stuff((select '+' + d from tb t where b = tb.b and c = tb.c for xml path('')) , 1 , 1 , '')
from tb
group by b , c
#9
select b , c , d = stuff((select ',' + d from tb t where b = tb.b and c = tb.c for xml path('')) , 1 , 1 , '')
from tb
group by b , c
这样差不多了.
from tb
group by b , c
这样差不多了.
#1
合并列值
#2
http://www.cnblogs.com/codeyu/archive/2010/05/25/1743474.html
利用 sql 的 xml 来实现合并. 具体 SQL 不帮你写了,参考上面的 一起学习下
#3
合并列值
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)
1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ''
SELECT @str = @str + ',' + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, '')
END
GO
-- 调用函数
SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ' <N value="', ','), '"/>', ''), 1, 1, '')
)N
drop table tb
/*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(2 行受影响)
*/
--SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, 'aa')
insert into tb values(1, 'bb')
insert into tb values(2, 'aaa')
insert into tb values(2, 'bbb')
insert into tb values(2, 'ccc')
go
select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '')
from tb
group by id
/*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc
(2 row(s) affected)
*/
drop table tb
#4
select min(a) a,b, d=stuff((select '+'+d from tb t where b=tb.b and c=tb.c for xml path('')), 1, 1, '')
from tb
group by b ,c
/*
a,b,d
1,1,ab+aa+cc
3,1,we+bb
2,2,cd
(3 行受影响)
#5
select min(a) a,b, d=stuff((select '+'+d from tb t where b=tb.b and c=tb.c for xml path('')), 1, 1, '')
from tb
group by b ,c
order by b
#6
+1
#7
--sql 2000
create function dbo.f_str(@b int,@c int) returns varchar(1000)
as
begin
declare @str varchar(1000)
select @str = isnull(@str + '+' , '') + cast(d as varchar) from tb where b = @b and c = @c
return @str
end
go
--调用函数
select b,c , d = dbo.f_str(b,c) from tb group by b, c
#8
--sql 2005
select b , c , d = stuff((select '+' + d from tb t where b = tb.b and c = tb.c for xml path('')) , 1 , 1 , '')
from tb
group by b , c
#9
select b , c , d = stuff((select ',' + d from tb t where b = tb.b and c = tb.c for xml path('')) , 1 , 1 , '')
from tb
group by b , c
这样差不多了.
from tb
group by b , c
这样差不多了.