When a user creates a new account on my website I want to check if the name already exists. I want this check to run when they leave the username input box and go to enter a password.
当用户在我的网站上创建新帐户时，我想检查名称是否已存在。我希望在他们离开用户名输入框并输入密码时运行此检查。
I tried :
我试过了 ：
<input type="text" onkeyup="check_user(this.value)"/>
4 个解决方案
#1
7
You need to use the "onblur" event. It fires when a control loses its focus, which seems to be exactly what you need.
您需要使用“onblur”事件。它会在控件失去焦点时触发，这似乎正是您所需要的。
#2
7
Call the function on the change event of text field:
在文本字段的change事件上调用该函数：
<input name="username" onChange="check_user(this.value);" type="text"/>
#3
2
Because you used onkeyup in your code example, it sounds like you are looking to call a function on every keystroke. If that is the case, then instead of onchange - which fires when the input loses focus - you should use oninput which will fire anytime there is a change inside of input.
因为您在代码示例中使用了onkeyup，所以听起来您希望在每次击键时调用函数。如果是这种情况，那么代替onchange--当输入失去焦点时触发 - 你应该使用oninput，它会在输入内部发生变化时触发。
#4
1
I think you are looking for check the duplication of user. you have to write server side code for that.
我认为你正在寻找检查用户的重复。你必须为此编写服务器端代码。
#1
7
You need to use the "onblur" event. It fires when a control loses its focus, which seems to be exactly what you need.
您需要使用“onblur”事件。它会在控件失去焦点时触发，这似乎正是您所需要的。
#2
7
Call the function on the change event of text field:
在文本字段的change事件上调用该函数：
<input name="username" onChange="check_user(this.value);" type="text"/>
#3
2
Because you used onkeyup in your code example, it sounds like you are looking to call a function on every keystroke. If that is the case, then instead of onchange - which fires when the input loses focus - you should use oninput which will fire anytime there is a change inside of input.
因为您在代码示例中使用了onkeyup，所以听起来您希望在每次击键时调用函数。如果是这种情况，那么代替onchange--当输入失去焦点时触发 - 你应该使用oninput，它会在输入内部发生变化时触发。
#4
1
I think you are looking for check the duplication of user. you have to write server side code for that.
我认为你正在寻找检查用户的重复。你必须为此编写服务器端代码。