I have a select query that returns data a table with different cases by Id, see below:
我有一个选择查询,通过Id返回具有不同情况的表的数据,请参见下文:
Case 1:
+--------+---------+
| RowNum | Size |
+--------+---------+
| 1 | large |
+--------+---------+
Case 2:
+--------+---------+
| RowNum | Size |
+--------+---------+
| 1 | small |
| 2 | x-large |
+--------+---------+
Case 3:
+--------+---------+
| RowNum | Size |
+--------+---------+
| 1 | small |
| 2 | small |
| 3 | x-large |
| 4 | large |
+--------+---------+
Case 4:
+--------+---------+
| RowNum | Size |
+--------+---------+
| 1 | large |
| 2 | medium |
| 3 | large |
+--------+---------+
Case 5:
+--------+---------+
| RowNum | Size |
+--------+---------+
| 1 | small |
| 2 | x-large |
| 3 | medium |
| 4 | large |
+--------+---------+
Case 6, 7, 8.....
案例6,7,8 ......
Note: all the returned table may have different rows and value, so it could be tens cases, and the row number just as a index with no meaning.
注意:所有返回的表可能有不同的行和值,因此它可能是十几个案例,行号只是一个没有意义的索引。
I need only one row returned with the largest size compared to the rows that the table has.
我只需要返回一行,其中最大的大小与表所具有的行相比。
For example:
- in Case 1, I only need the 'large' row;
- in Case 2, I only need the 'x-large' row;
- in Case 3, I only need the 'x-large' row;
- in Case 4, I only need the 'large' row;
- in Case 5, I only need the 'x-large' row;
在案例1中,我只需要'大'行;
在案例2中,我只需要'x-large'行;
在案例3中,我只需要'x-large'行;
在案例4中,我只需要'大'行;
在案例5中,我只需要'x-large'行;
Can anyone help me find a way how to get the result?
任何人都可以帮我找到如何获得结果的方法吗?
Solution can be stored procedures, functions, views, or queries.
解决方案可以是存储过程,函数,视图或查询。
Many thanks!
1 个解决方案
#1
1
Just to answer the presentation issue regardless of the logic you can use CASE over ORDER BY
只是为了回答演示问题而不管逻辑是什么,你可以使用CASE而不是ORDER BY
select top 1 *
from
table
order by (
case size
when 'x-large' then 4
when 'large' then 3
when 'medium' then 2
when 'small' then 1
else 0
end
) desc
#1
1
Just to answer the presentation issue regardless of the logic you can use CASE over ORDER BY
只是为了回答演示问题而不管逻辑是什么,你可以使用CASE而不是ORDER BY
select top 1 *
from
table
order by (
case size
when 'x-large' then 4
when 'large' then 3
when 'medium' then 2
when 'small' then 1
else 0
end
) desc