有时候我们需要按照in条件里的id顺序输出结果,可sql语句在不加order by的时候是按照asc排序的,下边的sql解决按照in条件顺序的id输出查询结果
mysql写法:
SELECT * FROM EVENT WHERE eventId IN(443,419,431,440,420,414,509) ORDER BY INSTR(',443,419,431,440,420,414,509,',CONCAT(',',eventId,','))
oracle写法:
select name from order where oderid in(111,222,333,444,555,666)order by instr('111,222,333,444,555,666',orderid)
sqlserver写法:
Select * From Product Where id in (1,1588,15782,9887,54) Order By charindex(','+ id +',', ',1,1588,15782,9887,54,')
分享一个SQL,让in的查询结果按顺序返回结果:SELECT * FROM `pd_customgroup` WHERE `gid` in(2732,2734,2733,99758,2735,109264) order by field(gid, 2732,2734,2733,99758,2735,109264)