--方案一:
declare @d datetime
set @d = getdate()
select top 10 * from Info where ID not in (select top 9990 ID from Info order by ID) order by ID
select [not in方法升序分页执行花费时间(毫秒)]=datediff(ms,@d,getdate()) --430ms
--方案二:
declare @s datetime
set @s = getdate()
select top 10 * from info where ID >=(select max(ID) from (select top 9991 ID from info order by ID) as T) order by ID
select [Max方法升序分页执行花费时间(毫秒)]=datediff(ms,@s,getdate()) --13ms
--方案三:
declare @q datetime
set @q = getdate()
select top 10 * from Info where ID <=(select min(ID) from (select top 9991 ID from Info order by ID desc) as T) order by ID desc
select [Min方法降序分页执行花费时间(毫秒)]=datediff(ms,@q,getdate())--10ms
--方案四:
declare @r datetime
set @r = getdate()
select top 10 * from
(
select row_number()over( order by id desc) as rowNumber,* from info ) T
where T.rowNumber>0
select [row_number()方法降序分页执行花费时间(毫秒)]=datediff(ms,@r,getdate())--3ms
--方案五:
with infos as
(
select r.*, row_number()over(order by r.id desc) as r
from [Info] r
)
select * from infos where r between 1 and 30;
方案五没有采取top的形式取数据,而是用了between,相同点都用了row_number()函数。根据平常的分页习惯,方案四、五效率最高,且性能相当.