视图中的多个强类型模型

I am trying to make a 'Create New' page in MVC 4. The page will have text fields and dropdown fields. I want the items listed in the dropdown box to come from another model.

我正在尝试在MVC 4中创建一个“创建新的”页面。页面将包含文本字段和下拉字段。我希望下拉框中列出的项目来自另一个模型。

Main Model: (ignore syntax as following code is a generic example)

主模型:(忽略语法，如下代码是一个通用示例)

public int MainID {get; set;}
public int location {get; set;}
...

someDetails Model:

someDetails模型:

public int detailID {get; set;}
public int MainID {get; set;}
...
public int actionID {get; set;}

Action Model:

操作模式:

public int actionID {get; set;}
public int location {get; set;}
public string action {get; set;}

SomeDetails carries additional information about Main and is linked by using mainID. I am interested in creating a 'Add Details' pages for someDetails. Part of this page will include a dropdown for Action that is based on the location field in main.

一些细节包含有关Main的附加信息，并通过使用mainID进行链接。我有兴趣为某些细节创建一个“添加细节”页面。这个页面的一部分将包含一个基于main中的location字段的下拉菜单。

What would be the best way to implement the dropdown box? I have a solution that involves passing possible values in the ViewBag, but I've seen this labeled bad practice. I was also thinking that it might be possible to change public int actionID {get; set;} to a type of <List>Action. If doing this method, I think I would have the constructor for someDetails populate the list? Would this cause performance issues when simply viewing a particular someDetails since it would try to create the list each time?

实现下拉框的最佳方式是什么?我有一个在ViewBag中传递可能的值的解决方案，但是我已经看到了这个标记为糟糕的实践。我还在想也许可以改变公共int actionID {get;将}设置为操作的类型。如果使用这个方法，我想我应该让someDetails的构造函数填充列表?这是否会导致性能问题，当仅仅查看特定的某些细节时，因为它将尝试每次创建列表?

Create action:

创建动作:

 public ActionResult Create(int id = -1)
    {
        if (id == -1)
        {
            //NOTE: INSERT REDIRECT HERE
        }
        someDetails model = new someDetails();
        model.MainID = id;
        return View(model);
    }

EDIT: As requested, better explanation of business logic The main model I have shown is modeled after an existing table that I am not able to change as it is part of a data warehouse that lives outside my control/group. I am creating an application which allows users to add someDetails in order to gain better visibility/tracking of some of this data. The Action model simply displays possible actions/actionIDs based on the location.

编辑:根据请求，更好地解释业务逻辑，我所展示的主要模型是模仿现有的表，我无法更改，因为它是位于我的控制/组之外的数据仓库的一部分。我正在创建一个应用程序，它允许用户添加一些细节，以便更好地查看/跟踪这些数据。动作模型仅仅根据位置显示可能的动作/动作。

My application will allow a user to search for or filter a set of items from the main model. They will be then allowed to add someDetails which will bring up a form which will contain some text fields and a dropdown list to pick an action. To get possible values for action, I would do something like SELECT * FROM Action a WHERE a.location = currentLocation

我的应用程序将允许用户从主模型中搜索或过滤一组项。他们将被允许添加一些细节，这些细节将包含一些文本字段和下拉列表来选择一个动作。为了获得可能的操作值，我将执行SELECT * FROM action a WHERE a。位置= currentLocation

1 个解决方案

#1

Just create a ViewModel with properties for each model... and that ViewModel can be populated in your controller and then passed to the view.

只需为每个模型创建一个带有属性的视图模型……这个ViewModel可以在控制器中填充，然后传递给视图。

EDIT: For DropDownLists:

编辑:dropdownlist:

In your ViewModel you need a property for the selected action id, and another to the list itself.

在您的ViewModel中，需要为所选的操作id和列表本身提供一个属性。

In the model:

在模型中:

public int actionId { get; set;}
public SelectList ListOfActions { get; set;}
//Other model members

In the View:

在视图:

@Html.DropDownListFor(model => model.actionId, Model.ListOfActions, "Select one action", new { @class = "yourclass" })

In your controller:

在你的控制器:

var model = new YourViewModel();
model.ListOfActions = new SelectList(this.GetListOfActions(), "ActionName", "ActionId", [here the selected action id in case you need it])

#1