如何从HttpResponse打印出返回的消息?

时间:2022-05-18 01:56:11

I have this code on my Android phone.

我的Android手机上有这个代码。

   URI uri = new URI(url);
   HttpPost post = new HttpPost(uri);
   HttpClient client = new DefaultHttpClient();
   HttpResponse response = client.execute(post);

I have a asp.net webform application that has in the page load this

我有一个asp.net webform应用程序,在页面加载这个

 Response.Output.Write("It worked");

I want to grab this Response from the HttpReponse and print it out. How do I do this?

我想从HttpReponse中获取此响应并将其打印出来。我该怎么做呢?

I tried response.getEntity().toString() but it just seems to print out the address in memory.

我尝试了response.getEntity()。toString()但它似乎打印出内存中的地址。

Thanks

谢谢

4 个解决方案

#1


38  

Use ResponseHandler. One line of code. See here and here for sample Android projects using it.

使用ResponseHandler。一行代码。有关使用它的示例Android项目,请参阅此处和此处。

public void postData() {
    // Create a new HttpClient and Post Header
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://www.yoursite.com/user");

    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("id", "12345"));
        nameValuePairs.add(new BasicNameValuePair("stringdata", "AndDev is Cool!"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        ResponseHandler<String> responseHandler=new BasicResponseHandler();
        String responseBody = httpclient.execute(httppost, responseHandler);
        JSONObject response=new JSONObject(responseBody);
    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }
} 

add combination of this post and complete HttpClient at - http://www.androidsnippets.org/snippets/36/

添加此帖子的组合并完成HttpClient - http://www.androidsnippets.org/snippets/36/

#2


8  

I would just do it the old way. It's a more bulletproof than ResponseHandler, in case you get different content types in the response.

我会以旧的方式做到这一点。如果您在响应中获得不同的内容类型,它比ResponseHandler更具防弹性。

ByteArrayOutputStream outstream = new ByteArrayOutputStream();
response.getEntity().writeTo(outstream);
byte [] responseBody = outstream.toByteArray();

#3


6  

I used the following code

我使用了以下代码

BufferedReader r = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

StringBuilder total = new StringBuilder();

String line = null;

while ((line = r.readLine()) != null) {
   total.append(line);
}
r.close();
return total.toString();

#4


3  

This code will return the entire response message in respond as a String, and status code in rsp, as an int.

此代码将返回整个响应消息作为字符串进行响应,并将状态代码作为int返回到rsp中。

respond = response.getStatusLine().getReasonPhrase();

rsp = response.getStatusLine().getStatusCode();`

#1


38  

Use ResponseHandler. One line of code. See here and here for sample Android projects using it.

使用ResponseHandler。一行代码。有关使用它的示例Android项目,请参阅此处和此处。

public void postData() {
    // Create a new HttpClient and Post Header
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://www.yoursite.com/user");

    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("id", "12345"));
        nameValuePairs.add(new BasicNameValuePair("stringdata", "AndDev is Cool!"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        ResponseHandler<String> responseHandler=new BasicResponseHandler();
        String responseBody = httpclient.execute(httppost, responseHandler);
        JSONObject response=new JSONObject(responseBody);
    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }
} 

add combination of this post and complete HttpClient at - http://www.androidsnippets.org/snippets/36/

添加此帖子的组合并完成HttpClient - http://www.androidsnippets.org/snippets/36/

#2


8  

I would just do it the old way. It's a more bulletproof than ResponseHandler, in case you get different content types in the response.

我会以旧的方式做到这一点。如果您在响应中获得不同的内容类型,它比ResponseHandler更具防弹性。

ByteArrayOutputStream outstream = new ByteArrayOutputStream();
response.getEntity().writeTo(outstream);
byte [] responseBody = outstream.toByteArray();

#3


6  

I used the following code

我使用了以下代码

BufferedReader r = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

StringBuilder total = new StringBuilder();

String line = null;

while ((line = r.readLine()) != null) {
   total.append(line);
}
r.close();
return total.toString();

#4


3  

This code will return the entire response message in respond as a String, and status code in rsp, as an int.

此代码将返回整个响应消息作为字符串进行响应,并将状态代码作为int返回到rsp中。

respond = response.getStatusLine().getReasonPhrase();

rsp = response.getStatusLine().getStatusCode();`