使用RAISERROR在SQL Server 2005中不起作用?

时间:2022-07-03 01:54:06

I have the following code below:

我有以下代码:

BEGIN TRY 

    BEGIN TRANSACTION
       -- DO SOMETHIING

    COMMIT TRAN

END TRY
BEGIN CATCH
   IF(@@TRANCOUNT > 0)
     ROLLBACK TRANSACTION

   RAISERROR(ERROR_MESSAGE(), ERROR_SEVERITY(), ERROR_STATE()) --ERROR: Incorrect syntax near 'ERROR_MESSAGE'.

END CATCH

However, the RAISERROR statement isn't working. What is wrong in the raise error statement?

但是,RAISERROR语句不起作用。提出错误声明有什么问题?

2 个解决方案

#1


8  

RAISERROR follows the same rules as any other stored procedure call. Parameters passed in must be a constant or a variable. You cannot pass a function directly as a parameter. See Executing Stored Procedures for documentation on this.

RAISERROR遵循与任何其他存储过程调用相同的规则。传入的参数必须是常量或变量。您不能直接将函数作为参数传递。有关此文档,请参阅执行存储过程。

/* Demo Code - Functions accept functions as parameters
               while stored procedures do not              */

create function dbo.fnDayOfWeek 
    (@date datetime) 
    returns int
as
begin
    declare @x int
    set @x = DATEPART(day,@date)
    return (@x)
end
go

/* Both statements are successful */
select dbo.fnDayOfWeek('2010-08-06')
go
select dbo.fnDayOfWeek(GETDATE())
go

drop function dbo.fnDayOfWeek
go

create procedure DayOfWeek
    @date datetime
as
begin
    select DATEPART(day,@date)
end
go

/* First call succeeds, second fails */
exec DayOfWeek @date = '2010-08-06'
go
exec DayOfWeek @date = getdate()
go

drop procedure DayOfWeek
go

#2


14  

Error is occurring because you directly using function in RaiseError so to avoid this try the below code Try this is working for me

发生错误是因为您直接在RaiseError中使用函数,所以为了避免这种尝试下面的代码尝试这对我有用

BEGIN CATCH
    DECLARE @ErrorMessage NVARCHAR(4000);
    DECLARE @ErrorSeverity INT;
    DECLARE @ErrorState INT;

    SELECT 
        @ErrorMessage = ERROR_MESSAGE(),
        @ErrorSeverity = ERROR_SEVERITY(),
        @ErrorState = ERROR_STATE();

    RAISERROR (@ErrorMessage, -- Message text.
               @ErrorSeverity, -- Severity.
               @ErrorState -- State.
               );
END CATCH;

#1


8  

RAISERROR follows the same rules as any other stored procedure call. Parameters passed in must be a constant or a variable. You cannot pass a function directly as a parameter. See Executing Stored Procedures for documentation on this.

RAISERROR遵循与任何其他存储过程调用相同的规则。传入的参数必须是常量或变量。您不能直接将函数作为参数传递。有关此文档,请参阅执行存储过程。

/* Demo Code - Functions accept functions as parameters
               while stored procedures do not              */

create function dbo.fnDayOfWeek 
    (@date datetime) 
    returns int
as
begin
    declare @x int
    set @x = DATEPART(day,@date)
    return (@x)
end
go

/* Both statements are successful */
select dbo.fnDayOfWeek('2010-08-06')
go
select dbo.fnDayOfWeek(GETDATE())
go

drop function dbo.fnDayOfWeek
go

create procedure DayOfWeek
    @date datetime
as
begin
    select DATEPART(day,@date)
end
go

/* First call succeeds, second fails */
exec DayOfWeek @date = '2010-08-06'
go
exec DayOfWeek @date = getdate()
go

drop procedure DayOfWeek
go

#2


14  

Error is occurring because you directly using function in RaiseError so to avoid this try the below code Try this is working for me

发生错误是因为您直接在RaiseError中使用函数,所以为了避免这种尝试下面的代码尝试这对我有用

BEGIN CATCH
    DECLARE @ErrorMessage NVARCHAR(4000);
    DECLARE @ErrorSeverity INT;
    DECLARE @ErrorState INT;

    SELECT 
        @ErrorMessage = ERROR_MESSAGE(),
        @ErrorSeverity = ERROR_SEVERITY(),
        @ErrorState = ERROR_STATE();

    RAISERROR (@ErrorMessage, -- Message text.
               @ErrorSeverity, -- Severity.
               @ErrorState -- State.
               );
END CATCH;