I'm having this error: error c2064: term does not evaluate to a function taking 0 arguments. The thing is the function takes 0 arguments and I call 0 arguments, and I don't understand what's wrong.
我有这个错误:error c2064: term不计算一个带0个参数的函数。这个函数取0个参数，我调用0个参数，我不明白是怎么回事。
RWLock* rwl = new RWLock();
std::thread t1(&RWLock::read);
That's the call to the function. And this is the function:
这就是对函数的调用。这是函数:
void read();
Does somebody know what the problem is? Thanks in advance!
有人知道问题出在哪里吗?提前谢谢!
2 个解决方案
#1
7
All non-static member functions have a hidden argument, that becomes the this pointer in the member function If you want to use a non-static member function as a thread, you have to provide this hidden argument when starting the thread:
所有非静态成员函数都有一个隐藏参数，它成为成员函数中的这个指针，如果你想使用一个非静态成员函数作为线程，你必须在启动线程时提供这个隐藏参数:
std::thread t1(&RWLock::read, rwl);
#2
2
I am pretty sure, that read() is not a static function. That is, you declared it as:
我很确定，read()不是一个静态函数。也就是说，你把它说成:
void read()
无效的read()
instead of:
而不是:
static void read()
静态孔隙read()
Non-static member function takes always one additional argument - implicit this pointer. Make read() static and it should work.
非静态成员函数总是附加一个参数——隐式这个指针。让read()静态，它应该工作。
If read() cannot be static, pass an additional argument to std::thread - a pointer to object, that read() will work on. In this case it should be rwl:
如果read()不是静态的，则将一个附加参数传递给std::thread——一个指向对象的指针，read()将继续工作。在这种情况下应该是rwl:
RWLock* rwl = new RWLock();
std::thread t1(&RWLock::read, rwl);
#1
7
All non-static member functions have a hidden argument, that becomes the this pointer in the member function If you want to use a non-static member function as a thread, you have to provide this hidden argument when starting the thread:
所有非静态成员函数都有一个隐藏参数，它成为成员函数中的这个指针，如果你想使用一个非静态成员函数作为线程，你必须在启动线程时提供这个隐藏参数:
std::thread t1(&RWLock::read, rwl);
#2
2
I am pretty sure, that read() is not a static function. That is, you declared it as:
我很确定，read()不是一个静态函数。也就是说，你把它说成:
void read()
无效的read()
instead of:
而不是:
static void read()
静态孔隙read()
Non-static member function takes always one additional argument - implicit this pointer. Make read() static and it should work.
非静态成员函数总是附加一个参数——隐式这个指针。让read()静态，它应该工作。
If read() cannot be static, pass an additional argument to std::thread - a pointer to object, that read() will work on. In this case it should be rwl:
如果read()不是静态的，则将一个附加参数传递给std::thread——一个指向对象的指针，read()将继续工作。在这种情况下应该是rwl:
RWLock* rwl = new RWLock();
std::thread t1(&RWLock::read, rwl);