T-SQL子字符串——分隔名和姓

I have a column which has FirstName and LastName together. I'm writing a report to separate the FirstName And LastName. How do I get the FirstName and LastName separated in T-SQL?

我有一个列，它有名和姓。我正在写一份报告，把名字和姓分开。如何在T-SQL中分离FirstName和LastName ?

10 个解决方案

#1

Assuming the FirstName is all of the characters up to the first space:

假设第一个名字是第一个空格前的所有字符:

SELECT
  SUBSTRING(username, 1, CHARINDEX(' ', username) - 1) AS FirstName,
  SUBSTRING(username, CHARINDEX(' ', username) + 1, 8000) AS LastName
FROM
  whereever

#2

The easiest way I can find to do it is:

我能找到的最简单的方法是:

SELECT 
  SUBSTRING(FullName, 1, CHARINDEX(' ', FullName) - 1) AS FirstName,
  REVERSE(SUBSTRING(REVERSE(FullName), 1, CHARINDEX(' ', REVERSE(FullName)) - 1)) AS LastName
FROM
  [PERSON_TABLE]

#3

This should work:

这应该工作:

Select  
    LTRIM(RTRIM(SUBSTRING(FullName, 0, CHARINDEX(' ', FullName)))) As FirstName
,   LTRIM(RTRIM(SUBSTRING(FullName, CHARINDEX(' ', FullName)+1, 8000)))As LastName
FROM TABLE

Edit: Adopted Aaron's and Jonny's hint with the fixed length of 8000 to avoid unnecessary calculations.

编辑:采用Aaron和Jonny的提示，固定长度为8000，避免不必要的计算。

#4

validate last name is blank

SELECT  
person.fullName,
(CASE WHEN 0 = CHARINDEX(' ', person.fullName) 
    then  person.fullName 
    ELSE SUBSTRING(person.fullName, 1, CHARINDEX(' ', person.fullName)) end) as first_name,  
(CASE WHEN 0 = CHARINDEX(' ', person.fullName) 
    THEN ''  
    ELSE SUBSTRING(person.fullName,CHARINDEX(' ', person.fullName), LEN(person.fullName) )end) last_name

FROM person

#5

This will take care of names like "Firstname Z. Lastname" and "First Z Last"

这将处理“Firstname Z. Lastname”和“First Z Last”等名称

SELECT
CASE 
    WHEN CHARINDEX(' ',name) = 0 THEN name
    WHEN CHARINDEX(' ',name) = PATINDEX('% _[., ]%',name) THEN RTRIM(SUBSTRING(name, 1, CHARINDEX(' ',name) + 2)) 
    ELSE SUBSTRING(name,1, CHARINDEX(' ',name))
END [firstname]
,CASE 
    WHEN CHARINDEX(' ',name) = 0 THEN ''
    WHEN CHARINDEX(' ',name) = PATINDEX('% _[., ]%',name) THEN LTRIM(SUBSTRING(name, CHARINDEX(' ',name) + 3,1000)) 
    ELSE SUBSTRING(name,CHARINDEX(' ',name)+1,1000)
END [lastname]
FROM [myTable]

#6

Here is a more elaborated solution with a SQL function:

下面是一个更复杂的SQL函数解决方案:

GetFirstname

CREATE FUNCTION [dbo].[ufn_GetFirstName]  
(  
 @FullName varchar(500)  
)  
RETURNS varchar(500)  
AS  
BEGIN  
 -- Declare the return variable here  
 DECLARE @RetName varchar(500)  

 SET @FullName = replace( replace( replace( replace( @FullName, '.', '' ), 'Mrs', '' ), 'Ms', '' ), 'Mr', '' )  

 SELECT   
  @RetName =   
    CASE WHEN charindex( ' ', ltrim( rtrim( @FullName ) ) ) &gt; 0 THEN left( ltrim( rtrim( @FullName ) ), charindex( ' ', ltrim( rtrim( @FullName  ) ) ) - 1 ) ELSE '' END  

 RETURN @RetName  
END

GetLastName

CREATE FUNCTION [dbo].[ufn_GetLastName]  
(  
 @FullName varchar(500)  
)  
RETURNS varchar(500)  
AS  
BEGIN  
 DECLARE @RetName varchar(500)  

 IF(right(ltrim(rtrim(@FullName)), 2) &lt;&gt; ' I')  
 BEGIN  
  set @RetName = left(   
   CASE WHEN   
    charindex( ' ', reverse( ltrim( rtrim(   
    replace( replace( replace( replace( replace( replace( @FullName, ' Jr', '' ), ' III', '' ), ' II', '' ), ' Jr.', '' ), ' Sr', ''), 'Sr.', '')  
    ) ) ) ) &gt; 0   
   THEN   
    right( ltrim( rtrim(   
    replace( replace( replace( replace( replace( replace( @FullName, ' Jr', '' ), ' III', '' ), ' II', '' ), ' Jr.', '' ), ' Sr', ''), 'Sr.', '')  
    ) ) , charindex( ' ', reverse( ltrim( rtrim(   
    replace( replace( replace( replace( replace( replace( @FullName, ' Jr', '' ), ' III', '' ), ' II', '' ), ' Jr.', '' ), ' Sr', ''), 'Sr.', '')  
    ) ) )  ) - 1 )   
   ELSE '' END  
  , 25 )  
 END  
 ELSE  
 BEGIN  
  SET @RetName = left(   
   CASE WHEN   
    charindex( ' ', reverse( ltrim( rtrim(   
    replace( replace( replace( replace( replace( replace( replace( @FullName, ' Jr', '' ), ' III', '' ), ' II', '' ), ' I', '' ), ' Jr.', '' ), ' Sr', ''), 'Sr.', '')  
    ) ) ) ) &gt; 0   
   THEN   
    right( ltrim( rtrim(   
    replace( replace( replace( replace( replace( replace( replace( @FullName, ' Jr', '' ), ' III', '' ), ' II', '' ), ' I', '' ), ' Jr.', '' ), ' Sr', ''), 'Sr.', '')  
    ) ) , charindex( ' ', reverse( ltrim( rtrim(   
    replace( replace( replace( replace( replace( replace( replace( @FullName, ' Jr', '' ), ' III', '' ), ' II', '' ), ' I', '' ), ' Jr.', '' ), ' Sr', ''), 'Sr.', '')  
    ) ) )  ) - 1 )   
   ELSE '' END  
  , 25 )  
 END  

 RETURN @RetName  
END

USE:

使用:

SELECT dbo.ufn_GetFirstName(Fullname) as FirstName, dbo.ufn_GetLastName(Fullname) as LastName FROM #Names

#7

You may have problems if the Fullname doesn't contain a space. Assuming the whole of FullName goes to Surname if there is no space and FirstName becomes an empty string, then you can use this:

如果全名不包含空格，您可能会有问题。假设如果没有空格，全名变成了姓，而FirstName变成了空字符串，那么您可以使用以下方法:

SELECT
  RTRIM(LEFT(FullName, CHARINDEX(' ', FullName))) AS FirstName,
  SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, 8000) AS LastName
FROM
  MyNameTable;

#8

I think below query will be helpful to split FirstName and LastName from FullName even if there is only FirstName. For example: 'Philip John' can be split into Philip and John. But if there is only Philip, because of the charIndex of Space is 0, it will only give you ''.

我认为下面的查询将有助于从FullName中拆分FirstName和LastName，即使只有FirstName。例如:“Philip John”可以分为Philip和John。但是如果只有Philip，因为空间的charIndex是0，它只会给你"

Try the below one.

下面的一个尝试。

declare @FullName varchar(100)='Philp John'

Select  
    LTRIM(RTRIM(SUBSTRING(@FullName, 0, CHARINDEX(' ', @FullName+' ')))) As FirstName
,   LTRIM(RTRIM(SUBSTRING(@FullName, CHARINDEX(' ', @FullName+' ')+1, 8000)))As LastName

Hope this will help you. :)

希望这能对你有所帮助。:)

#9

You could do this if firstname and surname are separated by space:

如果名字和姓氏用空格分开，你可以这样做:

SELECT SUBSTRING(FirstAndSurnameCol, 0, CHARINDEX(' ', FirstAndSurnameCol)) Firstname,
SUBSTRING(FirstAndSurnameCol, CHARINDEX(' ', FirstAndSurnameCol)-1, LEN(FirstAndSurnameCol)) Surname FROM ...

#10

The code below works with Last, First M name strings. Substitute "Name" with your name string column name. Since you have a period as a final character when there is a middle initial, you would replace the 2's with 3's in each of the lines (2, 6, and 8)- and change "RIGHT(Name, 1)" to "RIGHT(Name, 2)" in line 8.

下面的代码使用最后的，第M个名称字符串。用您的名字字符串列名替换“Name”。因为在中间的初始阶段，你有一个作为最终字符的周期，你将在每一行(2、6和8)中替换2的3，并且在第8行中将“RIGHT(Name, 1)”改为“RIGHT(Name, 2)”。

SELECT  SUBSTRING(Name, 1, CHARINDEX(',', Name) - 1) LastName ,
CASE WHEN LEFT(RIGHT(Name, 2), 1) <> ' '
     THEN LTRIM(SUBSTRING(Name, CHARINDEX(',', Name) + 1, 99))
     ELSE LEFT(LTRIM(SUBSTRING(Name, CHARINDEX(',', Name) + 1, 99)),
               LEN(LTRIM(SUBSTRING(Name, CHARINDEX(',', Name) + 1, 99)))
               - 2)
END FirstName ,
CASE WHEN LEFT(RIGHT(Name, 2), 1) = ' ' THEN RIGHT(Name, 1)
     ELSE NULL
END MiddleName

#1