I have a very old database I made when I was still learning PHP and MySQL. If I populate:
我有一个很旧的数据库,我在学习PHP和MySQL时做的。如果我填充:
SELECT * FROM Jobs WHERE (date BETWEEN 'Aug.01 2016' AND 'Aug.31 2016')
I can actually populate rows
我可以填充行
Found rows: 4 Warnings: 0 Duration for 1 query: 0.000 sec.
找到的行:4个警告:1个查询0持续时间:0.000秒。
But once I change my month (moving the range from Aug 1 to July 1):
但是一旦我改变了我的月份(从8月1日到7月1日):
SELECT * FROM Jobs WHERE (date BETWEEN 'Jul.01 2016' AND 'Aug.31 2016')
I got nothing even so the range July 1 ~ Aug 31 includes Aug 1 ~ Aug 31 (from previous example), which should populate at least 4 rows
7月1日~ 8月31日期间,我没有得到任何东西,包括8月1日~ 8月31日(之前的例子),应该至少填充4行。
Found rows: 0 Warnings: 0 Duration for 1 query: 0.016 sec.
发现行:0警告:1查询持续时间:0.016秒。
Is there a way I can populate the rows even they have different month?
是否有一种方法我可以填充行,即使它们有不同的月份?
1 个解决方案
#1
3
You need to first convert your date string to a valid date:
您需要首先将您的日期字符串转换为一个有效的日期:
SET @date := 'Aug.01 2016';
SELECT STR_TO_DATE(@date,'%M.%d %Y');
Output(yyyy-mm-dd): 2016-08-01
输出(yyyy-mm-dd):2016-08-01
Now use this in your query to search for result having dates between 2016-07-01 & 2016-08-31
.
现在,在您的查询中使用它来搜索日期为2016-07-01和2016-08-31的结果。
SELECT
*
FROM Jobs
WHERE STR_TO_DATE(date,'%M.%d %Y') BETWEEN '2016-07-01' AND '2016-08-31';
Note: But date should be stored in a date
datatype column. It's high time you converted the datatype
to date
of your date
column.
注意:但是日期应该存储在日期数据类型列中。现在是您将数据类型转换为date列的时候了。
In order to do that follow the steps below:
为了做到这一点,请遵循以下步骤:
ALTER TABLE Jobs
ADD new_date_column date;
UPDATE Jobs
SET new_date_column = STR_TO_DATE(date,'%M.%d %Y');
ALTER TABLE Jobs DROP COLUMN `date`;
ALTER TABLE Jobs CHANGE COLUMN `new_date_column` `date` date;
Steps in a nut shell:
坚果壳中的步骤:
-
Add a new column in
Jobs
table of typedate
.在类型为date的作业表中添加一个新的列。
-
Now update this new column with the values from your
date
column after converting to a valid date.现在,在转换到一个有效日期之后,用date列中的值更新这个新的列。
-
You don't need that
date
column. So drop it.你不需要那个日期栏。所以把它。
-
Now rename the newly created column to
date
.现在将新创建的列重命名为date。
#1
3
You need to first convert your date string to a valid date:
您需要首先将您的日期字符串转换为一个有效的日期:
SET @date := 'Aug.01 2016';
SELECT STR_TO_DATE(@date,'%M.%d %Y');
Output(yyyy-mm-dd): 2016-08-01
输出(yyyy-mm-dd):2016-08-01
Now use this in your query to search for result having dates between 2016-07-01 & 2016-08-31
.
现在,在您的查询中使用它来搜索日期为2016-07-01和2016-08-31的结果。
SELECT
*
FROM Jobs
WHERE STR_TO_DATE(date,'%M.%d %Y') BETWEEN '2016-07-01' AND '2016-08-31';
Note: But date should be stored in a date
datatype column. It's high time you converted the datatype
to date
of your date
column.
注意:但是日期应该存储在日期数据类型列中。现在是您将数据类型转换为date列的时候了。
In order to do that follow the steps below:
为了做到这一点,请遵循以下步骤:
ALTER TABLE Jobs
ADD new_date_column date;
UPDATE Jobs
SET new_date_column = STR_TO_DATE(date,'%M.%d %Y');
ALTER TABLE Jobs DROP COLUMN `date`;
ALTER TABLE Jobs CHANGE COLUMN `new_date_column` `date` date;
Steps in a nut shell:
坚果壳中的步骤:
-
Add a new column in
Jobs
table of typedate
.在类型为date的作业表中添加一个新的列。
-
Now update this new column with the values from your
date
column after converting to a valid date.现在,在转换到一个有效日期之后,用date列中的值更新这个新的列。
-
You don't need that
date
column. So drop it.你不需要那个日期栏。所以把它。
-
Now rename the newly created column to
date
.现在将新创建的列重命名为date。