如何从剩余时间中减去时间?

时间:2022-12-26 01:28:08

Using JavaScript, How can I subtract from HH:MM:SS?

使用JavaScript,我如何减去HH:MM:SS?

For example, I have 12:54:45 and I want to subtract 11:35:53 for remaining time in 4732 seconds

例如,我有12:54:45而且我想在4732秒内减去剩余时间的11:35:53

3 个解决方案

#1


3  

var first = (new Date('Jan 01, 2000 12:54:45')).getTime();
var second = (new Date('Jan 01, 2000 11:35:53')).getTime(); 
var differenceInSeconds = (second - first) / 1000;
// 4732

I chose 2000-01-01 as the date, as it does not matter as long it is the same. We only want to calculate the difference.

我选择2000-01-01作为日期,因为它并不重要,只要它是相同的。我们只想计算差异。

#2


1  

This works

(Date.parse('January 1, 1970 12:54:45') - Date.parse('January 1, 1970 11:35:53')) / 1000

Output is 4732

输出为4732

#3


1  

There are libraries that makes possible to manipulate dates in an easy way: moment.js and day.js are two examples of choice.

有些库可以轻松地操作日期:moment.js和day.js是两个选择的例子。

// moment.js example
moment()
  .add(7, 'days')
  .subtract(1, 'months')
  .year(2009)
  .hours(0)
  .minutes(0)
  .seconds(0);

More...

// day.js example
dayjs().add(7, 'day');

More...

Also, for seconds manipulation, Unix time can be useful. It allows to describe time as the number of seconds elapsed since 1st January 1970.

此外,对于秒操作,Unix时间可能很有用。它允许将时间描述为自1970年1月1日以来经过的秒数。

#1


3  

var first = (new Date('Jan 01, 2000 12:54:45')).getTime();
var second = (new Date('Jan 01, 2000 11:35:53')).getTime(); 
var differenceInSeconds = (second - first) / 1000;
// 4732

I chose 2000-01-01 as the date, as it does not matter as long it is the same. We only want to calculate the difference.

我选择2000-01-01作为日期,因为它并不重要,只要它是相同的。我们只想计算差异。

#2


1  

This works

(Date.parse('January 1, 1970 12:54:45') - Date.parse('January 1, 1970 11:35:53')) / 1000

Output is 4732

输出为4732

#3


1  

There are libraries that makes possible to manipulate dates in an easy way: moment.js and day.js are two examples of choice.

有些库可以轻松地操作日期:moment.js和day.js是两个选择的例子。

// moment.js example
moment()
  .add(7, 'days')
  .subtract(1, 'months')
  .year(2009)
  .hours(0)
  .minutes(0)
  .seconds(0);

More...

// day.js example
dayjs().add(7, 'day');

More...

Also, for seconds manipulation, Unix time can be useful. It allows to describe time as the number of seconds elapsed since 1st January 1970.

此外,对于秒操作,Unix时间可能很有用。它允许将时间描述为自1970年1月1日以来经过的秒数。