I have this tables:
我有这个表:
TABLE addonlist_final
表addonlist_final
TABLE addons
表插件
First, I have to JOIN
the same addon_id
so I can get all the needed details(which I've already done). Then I want to JOIN
the column
with the same identity(addon_id) in the table
then add the quantity to each other.
首先,我必须加入相同的addon_id,以便获得所需的所有细节(我已经这样做了)。然后,我要在表中加入具有相同标识(addon_id)的列,然后互相添加数量。
So far I have this code:
到目前为止,我有这个代码:
<?php
include("conn.php");
echo "<table border='1' >";
echo "<tr>";
echo "<th>Description</th>";
echo "<th>Price</th>";
echo "<th>Qty</th>";
echo "<th>Total Cost</th>";
echo "</tr>";
$totaldue = 0;
$currentaddons = mysql_query("SELECT a.*, af.*
FROM addons AS a, addonlist_final AS af
WHERE a.addon_id = af.faddon_id and af.ftransac_id='2685'
ORDER BY af.timef DESC
");
while($rows = mysql_fetch_assoc($currentaddons)){
$desc = $rows['description'];
$price = $rows['price'];
$qty = $rows['quantity'];
$totalcost = $price * $qty;
$totaldue += $price * $qty;
echo "<tr>";
echo "<td>$desc</td>";
echo "<td>$price</td>";
echo "<td>$qty</td>";
echo "<td>$totalcost</td>";
echo "</tr>";
}
echo "</table>";
echo "<h3>Total Due: ".number_format($totaldue)."</h3>";
?>
This shows me this:
这说明我这个:
What I want to show is:
我想展示的是:
Is this possible with just one query? Thanks in advance :)
只有一个查询可能吗?提前谢谢:)
1 个解决方案
#1
4
You uave to use group by
你必须使用团体by
SELECT a.description, sum(af.quantity) as quantity,price
FROM addons AS a, addonlist_final AS af
WHERE a.addon_id = af.faddon_id and af.ftransac_id='2685'
group by a.description
ORDER BY af.timef DESC
#1
4
You uave to use group by
你必须使用团体by
SELECT a.description, sum(af.quantity) as quantity,price
FROM addons AS a, addonlist_final AS af
WHERE a.addon_id = af.faddon_id and af.ftransac_id='2685'
group by a.description
ORDER BY af.timef DESC